The correct answer is
C.276
Answer:
2.2*10^5
Step-by-step explanation:
to write a # in scientific notation change the # to decimal form.
so 2.2
then move the decimal point to the right until you get the original #
Answer:
692
Step-by-step explanation:
Inorder to find the height, you miust plug in 0.05s for all times (t)
h(f) = -490t^2 + 75t + 12
h(f) = -490 • 0.05^2 + 75 • 0.05 + 12
Next follow PEMDAS from left to right.
(MD reversible, AS reversible)
(parentheses, exponents, multiply, divide, add, subtract)
parentheses~ nothing to simplify with parentheses
exponents~ h(f) = -490 • 0.0025 + 75 • 0.05 +12
multiply~ h(f) = -1.225 + 3.75 +12
divide~ nothing to simplify with division
add~ h(f) = 14.525
subtract~ nothing to simplify with subtraction
DON'T FORGET UNITS!
Answer: h(f) = 14.525 cm
Answer:
Step-by-step explanation:
REcall the following definition of induced operation.
Let * be a binary operation over a set S and H a subset of S. If for every a,b elements in H it happens that a*b is also in H, then the binary operation that is obtained by restricting * to H is called the induced operation.
So, according to this definition, we must show that given two matrices of the specific subset, the product is also in the subset.
For this problem, recall this property of the determinant. Given A,B matrices in Mn(R) then det(AB) = det(A)*det(B).
Case SL2(R):
Let A,B matrices in SL2(R). Then, det(A) and det(B) is different from zero. So
.
So AB is also in SL2(R).
Case GL2(R):
Let A,B matrices in GL2(R). Then, det(A)= det(B)=1 is different from zero. So
.
So AB is also in GL2(R).
With these, we have proved that the matrix multiplication over SL2(R) and GL2(R) is an induced operation from the matrix multiplication over M2(R).