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Harrizon [31]
2 years ago
15

Change the subject of the equation v = u + at to a.

Mathematics
1 answer:
emmasim [6.3K]2 years ago
8 0
<h3>Answer ↓</h3>

<h3>Calculations ↓</h3>

In order to make a the subject of this equation , we need to get a by itself .

The current equation is :

v = u + at

Subtract u on both sides :

v-u=at

Now, divide by t on both sides :

v-u/t=a

<h3>So the formula looks like ↓</h3>

\boxed{\\\begin{minipage}{3cm}Equation \\ a=$\displaystyle\frac{v-u}{t} $ \\ \end{minipage}}

hope helpful ~

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2^5×8^4/16=2^5×(2^a)4/2^4=2^5×2^b/2^4=2^c<br>A=<br>B=<br>C= <br>Please I'm gonna fail math
aleksley [76]

9514 1404 393

Answer:

  a = 3, b = 12, c = 13

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)/(a^c) = a^(b-c)

  (a^b)^c = a^(bc)

___

You seem to have ...

  \dfrac{2^5\times8^4}{16}=\dfrac{2^5\times(2^3)^4}{2^4}\qquad (a=3)\\\\=\dfrac{2^5\times2^{3\cdot4}}{2^4}=\dfrac{2^5\times2^{12}}{2^4}\qquad (b=12)\\\\=2^{5+12-4}=2^{13}\qquad(c=13)

_____

<em>Additional comment</em>

I find it easy to remember the rules of exponents by remembering that <em>an exponent signifies repeated multiplication</em>. It tells you how many times the base is a factor in the product.

  2\cdot2\cdot2 = 2^3\qquad\text{2 is a factor 3 times}

Multiplication increases the number of times the base is a factor.

  (2\cdot2\cdot2)\times(2\cdot2)=(2\cdot2\cdot2\cdot2\cdot2)\\\\2^3\times2^2=2^{3+2}=2^5

Similarly, division cancels factors from numerator and denominator, so decreases the number of times the base is a factor.

  \dfrac{(2\cdot2\cdot2)}{(2\cdot2)}=2\\\\\dfrac{2^3}{2^2}=2^{3-2}=2^1

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oksano4ka [1.4K]

Answer:

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Step-by-step explanation:

Line Q is practically in the middle of the dots. It is called a trend line btw. :)

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