Answer:
- 321 adult tickets
- 227 child tickets
Step-by-step explanation:
This sort of problem is easily solved by defining a variable to be the quantity of the higher-value contributor. Here, we can let x represent the number of adult tickets. Then total revenue is ...
6.50x +3.50(548-x) = 2881
3x +1918 = 2881 . . . . . . . . . . . . eliminate parentheses, collect terms
3x = 963 . . . . . . . . . . . . . . . . . . subtract 1918
x = 321 . . . . . . . . . . . . . . . . . . . . divide by 3
548-x = 548 -321 = 227 . . . . . .number of child tickets
321 adult tickets and 227 child tickets were sold.
1+5=6 so 6/8
Simplifying 6/8 is 3/4
Answer:
Kindly check explanation
Step-by-step explanation:
Given that :
Upper level seat = $25
Mid level seat = $40
Number of tickets to give away is at least 25
Budget constraint = $1000
part A: write a system of two inequalities that describe this situation
Number of tickets constraint:
Upper level + mid level ≥ 25
u + m ≥ 25
Cost constraint :
$25u + $40m ≤ $1000
Part B:
Give away 10 upper level seat tickets and 15 mid level seat tickets
16 dollars because it's 2 dollars per meter wide and it's 8 meters so 8x2=16