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Leya [2.2K]
3 years ago
15

Which mathematical statements are true?

Mathematics
1 answer:
Over [174]3 years ago
4 0

Answer:

1) If 3 is an odd number, then 3 times 3 is an even number.

False because multiplying odd number by an odd number also gives an odd number.

2) If 6 is less than 7, then 4 is greater than 7.

False because 4 is smaller than 6. As 6 is smaller than 7 then 4 must also be smaller.

3) Six is divisible by 3, and 10 is a multiple of 2.

True. 6/3 = 2 and 2 x 5 = 10. Both the conditions are true so it is also true.

4) The average of the data is greater than the largest value in the data, or it’s less than the largest value in the data.

True.

We have two conditions in this statement and an 'or' between them. One of the conditions is true that is "average is less than the largest value in the data". So the statement as a whole is true.

5) The slope of a linear graph is its rate of change, and the graph’s y-intercept is the initial value.

True.

6) If an equilateral triangle has equal angles, then all its angles will measure 45°.

False.

A triangle has 3 angles whose sum = 180 degrees.

For equilateral triangle each angle will measure 180/3= 60 degrees.

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Read 2 more answers
Use the quadratic formula to solve x^2 -3x - 5 = 0. Round to two decimal places.
Evgen [1.6K]

Answer:

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

x=\frac{3+\sqrt{29}}{2},\:x=\frac{3-\sqrt{29}}{2}

Step-by-step explanation:

Given the equation

x^2\:-3x\:-\:5\:=\:0

solving with the quadratic formula

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-3,\:c=-5

x_{1,\:2}=\frac{-\left(-3\right)\pm \sqrt{\left(-3\right)^2-4\cdot \:1\cdot \left(-5\right)}}{2\cdot \:1}

x_{1,\:2}=\frac{-\left(-3\right)\pm \sqrt{29}}{2\cdot \:1}

separating the solutions

x_1=\frac{-\left(-3\right)+\sqrt{29}}{2\cdot \:1},\:x_2=\frac{-\left(-3\right)-\sqrt{29}}{2\cdot \:1}

solving

x=\frac{-\left(-3\right)+\sqrt{29}}{2\cdot \:\:1}

  =\frac{3+\sqrt{29}}{2\cdot \:1}

  =\frac{3+\sqrt{29}}{2}

also solving

\:x=\frac{-\left(-3\right)-\sqrt{29}}{2\cdot \:\:1}

  =\frac{3-\sqrt{29}}{2\cdot \:1}

  =\frac{3-\sqrt{29}}{2}

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

x=\frac{3+\sqrt{29}}{2},\:x=\frac{3-\sqrt{29}}{2}

7 0
3 years ago
How many solutions does the system of equations have?
statuscvo [17]
5x - 20y = 60...reduce by dividing by 5
x - 4y = 12
this is the same as the other equation....therefore, it is the same line...meaning infinite solutions
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y - 7x = -14
y = 7x - 14.....slope = 7, y int = -14

7y - 49x = -2
7y = 49x - 2
y = 7x - 2/7.....slope is 7, y int is -2/7

if the slopes are the same, but the y int are different, then u have a parallel lines with no solutions
5 0
4 years ago
How do you solve for M in the formula?<br>Give Steps Please!​
Murljashka [212]

Answer:

m = \frac{gs^{2}}{10}

Step-by-step explanation:

g = 10(\frac{m}{s^{2} })

simplify:

g = \frac{10m}{s^{2}}

multiply both sides by s²:

gs² = 10m

divide both sides by 10:

m = \frac{gs^{2}}{10}

7 0
3 years ago
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