610grams that is the maxium because if you do 100+500+10 which is 610
Explanation:
Atomic number is the sum of total number of protons present in an element. And, each element of the periodic table will have a different atomic number. Whereas atomic mass is defined as the sum of total number of protons and neutrons present in an atom.
Atomic number of bromine is 35 which means that it contains 35 protons and the number of neutrons present in it are as follows.
atomic mass = no. of protons + no. of neutrons
80 = 35 + no. of neutrons
no. of neutrons = 80 - 35
= 45
In a neutral atom, the no. of protons is equal to the no. of electrons. As
has one negative charge which means that there are 36 electrons and 35 protons present in a
ion.
Atomic number of barium is 56 and no. of neutrons present in barium are as follows.
atomic mass = no. of protons + no. of neutrons
137 = 56 + no. of neutrons
no. of neutrons = 137 - 56
= 81
As
has one positive charge. So, it contains 55 electrons and 56 protons. Formula of its oxide is BaO
Atomic number of aluminium is 27 so, it has 27 protons. As
has a 3+ charge so, the number of electrons present in it will be 25.
Answer:
The blood sample has [H⁺] that is one million times lower than the [H⁺] of gastric juice.
Explanation:
To know the the correct answer to the question, we obtained obtained the hydrogen ion concentration [H⁺] of the blood and gastric juice. This can be obtained as follow:
For Blood sample:
pH = 7.4
Concentration of Hydrogen ion for blood [H⁺]₁ =?
pH = – Log [H⁺]₁
7.4 = – Log [H⁺]₁
Divide both side by –1
– 7.4 = Log [H⁺]₁
Take the antilog of – 7.4
[H⁺]₁ = Antilog (–7.4)
[H⁺]₁ = 3.98×10¯⁸ M
Thus, the concentration of Hydrogen ion for blood [H⁺]₁ is 3.98×10¯⁸ M
For Gastric juice:
pH = 1.4
Concentration of Hydrogen ion for gastric juice [H⁺]₂ =?
pH = – Log [H⁺]₂
1.4 = – Log [H⁺]₂
Divide both side by –1
– 1.4 = Log [H⁺]₂
Take the antilog of – 1.4
[H⁺]₂ = Antilog (–1.4)
[H⁺]₂ = 3.98×10¯² M
Thus, the concentration of Hydrogen ion for gastric juice [H⁺]₂ is 3.98×10¯² M
Finally, we shall compare the hydrogen ion concentration [H⁺] of the blood and gastric juice. This can be obtained as follow:
Concentration of Hydrogen ion for blood [H⁺]₁ = 3.98×10¯⁸ M
Concentration of Hydrogen ion for gastric juice [H⁺]₂ = 3.98×10¯² M
[H⁺]₁ / [H⁺]₂ = 3.98×10¯⁸ / 3.98×10¯²
[H⁺]₁ / [H⁺]₂ = 1×10¯⁶
Cross multiply
[H⁺]₁ = [H⁺]₂ × 1×10¯⁶
[H⁺]₁ = [H⁺]₂ / 1000000
From the calculations made above, the blood sample has [H⁺] that is one million times lower than the [H⁺] of gastric juice.
Answer: The molar concentration of
in the solution is 0.2 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
![Molarity=\frac{n\times 1000}{V_s}](https://tex.z-dn.net/?f=Molarity%3D%5Cfrac%7Bn%5Ctimes%201000%7D%7BV_s%7D)
where,
n= moles of solute =![\frac{\text {given mass}}{\text {molar mass}}=\frac{1.77g}{171g/mol}=0.010](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7Bgiven%20mass%7D%7D%7B%5Ctext%20%7Bmolar%20mass%7D%7D%3D%5Cfrac%7B1.77g%7D%7B171g%2Fmol%7D%3D0.010)
= volume of solution in ml = 100 ml
![Molarity=\frac{0.010\times 1000}{100}=0.1M](https://tex.z-dn.net/?f=Molarity%3D%5Cfrac%7B0.010%5Ctimes%201000%7D%7B100%7D%3D0.1M)
![Ba(OH)_2\rightarrow Ba^{2+}+2OH^-](https://tex.z-dn.net/?f=Ba%28OH%29_2%5Crightarrow%20Ba%5E%7B2%2B%7D%2B2OH%5E-)
As 1 mole of
gives 2 moles of ![OH^-](https://tex.z-dn.net/?f=OH%5E-)
Thus 0.1 moles of
gives =
moles of ![OH^-](https://tex.z-dn.net/?f=OH%5E-)
The molar concentration of
in the solution is 0.2 M
Answer:
A disease caused by microorganisms that invade tissue.