Suppose 200.0 mL of a 2.50 M solution of sodium hydroxide is combined with 400.0 mL of a 1.50 M solution of iron(III) nitrate. W
hat is the theoretical yield of precipitate? If 14.8 g of the precipitate actually formed, what is the percent yield?
1 answer:
Answer: 83%
Explanation:
The detailed solution is shown in the image attached. First we must work out the balanced reaction equation because accurate solution of the problem must be based on the stoichiometry of the reaction. From the given concentration and volume of reactants, we calculate the amount of substance reacted hence identify the limiting reactant. Lastly we use simple proportion to obtain the theoretical yield of the precipitate. This is now used to calculate the actual yield as shown in the solution attached.
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The rate of a reaction would be one-fourth.
<h3>Further explanation</h3>Given
Rate law-r₁ = k [NO]²[H2]
Required
The rate of a reaction
Solution
The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.
Can be formulated:
Reaction: aA ---> bB
or
The concentration of NO were halved, so the rate :
Answer : The heat of the reaction is -221.6 kJ
Explanation :
Heat released by the reaction = Heat absorbed by the calorimeter
where,
= heat released by the reaction = ?
= heat absorbed by the calorimeter
= specific heat of calorimeter =
= change in temperature =
Now put all the given values in the above formula, we get:
As,
So,
Thus, the heat of the reaction is -221.6 kJ