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Anna35 [415]
3 years ago
7

What is an equation of the line that is parallel to y=-4x - 5 and passes through the point (-2, 6)?

Mathematics
1 answer:
Alex73 [517]3 years ago
3 0

Answer:

B.) y=-4x-2

Step-by-step explanation:

If the line is parallel, the slope is the same

y = -4x-5 has a slope of -4, so the new line has a slope of -4

We have a slope and a point, so we can use point slope form

y-y1 = m(x-x2)

y-6 = -4(x--2)

y-6 = -4(x+2)

Distribute

y-6 =-4x -8

Add 6 to each side

y-6+6 = -4x-8+6

y = -4x-2

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Read 2 more answers
What simple interest rate would allow $6000 to grow to an amount of $14550 in 10 years?
Harman [31]

Answer:

\boxed{ \bold{ \huge{  \boxed{ \sf{ \: 14.25 \: \% \: }}}}}

Step-by-step explanation:

Given,

Principal ( P ) = $ 6000

Amount ( A ) = $ 14550

Time ( T ) = 10 years

Rate ( R ) = ?

<u>Finding </u><u>the </u><u>Interest</u>

The sum of principal and interest is called an amount.

From the definition,

\boxed{ \sf{Amount =  \: Principal + Interest}}

plug the values

⇒\sf{14550 = 6000 + Interest}

Swap the sides of the equation

⇒\sf{6000 + Interest = 14550}

Move 6000 to right hand side and change its sign

⇒\sf{Interest = 14550 - 6000}

Subtract 6000 from 14550

⇒\sf{Interest = \: 8550 \: }

Interest = $ 8550

<u>Finding </u><u>the </u><u>rate </u>

{ \boxed{ \sf{Rate =  \frac{Interest \times 100}{Principal \times Time}}}}

plug the values

⇒\sf{ Rate = \frac{8550  \times 100}{6000 \times 10} }

Calculate

⇒\sf{Rate =  \frac{855000}{60000} }

⇒\sf{Rate = 14.25 \: \% \: }

Hope I helped!

Best regards!!

8 0
3 years ago
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