FIRST SOLUTION!
first number = x
second number = x+2
third number = x+4
fourth number=x+6
fifth number=x+8
sixth number=x+10
seventh number=x+12
add all of those up and combine like terms to get 7x+42=357. Now subtract 42 from both sides to get 7x=315. Next, divide both sides by 7 to get x=45. To get the numbers, plug in 45 for x.
Your numbers should be 45,47,49,51,53,55, and 57.
Given x ^2 −3x+2=0
x ^2 −2x−1x+2=0
(Resolving the expression)
x(x−2)−1(x−2)=0 (Taking common factors)
(x−2)(x−1)=0 (Taking common factors)
∴x−2=0 or x−1=0 (Equating each factor to zero)
∴x=2 or x=1
∴2 and 1 are the roots of x ^2 −3x+2=0
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<em><u>Thanks</u></em><em><u>☸</u></em><em><u>.</u></em>
Answer:
Its either C. or D.
Step-by-step explanation:
Answer:well for the first one I am not sure but I think that since four is over the x there should be 4/x + 3 so tragically I don’t know the answer but I think it should be 12 the x should be 12 because 4x3=12 so yea 12
Step-by-step explanation:and for the other one I don’t know but ima try it should be two because 2x2=4 and so y=1-2x2-4 that’s what I think sorry. I got it wrong and do good on your test for me please