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3 years ago

-0.2x = 1.6 what does x equal

Mathematics

2 answers:

Colt1911 [192]3 years ago

4 0

Divide both sides of the equation by -0.2
x=-8

Sonbull [250]3 years ago

3 0

-0,2x = 1,6 *(-1)
0,2x = -1,6
x = -1,6 / 0,2
x = -16/2
x = -8

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FINDDD VALUE OF Y!!!!

solmaris [256]

Answer:

The sum of the internal ángles = 360°

(3y+40)° and (3x-70°) are suplementary angles = 180°

then:

(3x-70) + (3y+40) + 120 + x = 360 ⇒ first eq.

(3y+40) + (3x-70) = 180 ⇒ second eq

development:

from the first eq.

3x + x + 3y = 360 + 70 - 40 - 120

4x + 3y = 430 - 160

4x + 3y = 270 ⇒ third eq.

3y = 270 - 4x

y = (270 - 4x) / 3 ⇒ fourth eq.

from the secon eq.:

3y + 3x = 180 + 70 - 40

3y + 3x = 250 - 40

3y + 3x = 210 ⇒ fifth eq.

multiply by -1 the fifth eq and sum with the third eq.

-3y - 3x = -210 ⇒ (fifth eq. *-1)

3y + 4x = 270

⇒ 0 + x = 60

x = 60°

from the fourth eq.

y = (270-4x)/3

y = (270-(4*60)) / 3

y = (270 - 240) / 3

y = 30/3

y = 10°

Probe:

from the first eq.

(3x-70) + (3y+40) + 120 + x = 360

3*60 - 70 + 3*10 + 40 + 120 + 60 = 360

180 - 70 + 30 + 40 + 120 + 60 = 360

180 + 30 + 40 + 120 + 60 - 70 = 360

430 - 70 = 360

Answer:

y = 10

7 0

3 years ago

How do you do -2(t + 4)

Troyanec [42]

-2 (t+4)= -2 (t)+-2 (4)= -2t-8

7 0

3 years ago

Read 2 more answers

Solve the differential equation by variation of parameters, subject to the initial conditions y(0) = 1, y'(0) = 0. 36y'' − y = x

viktelen [127]

Try this solution, note, checking was not performed.

5 0

3 years ago

Please help this is confusing:(

topjm [15]

The answer would be 17

6 0

3 years ago

someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your

Lunna [17]

Answer:

Part A) The area of the figure is $24\ units^{2}$

Part B) The perimeter of the figure is $20\ units$

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

$A=\frac{1}{2}bh$

<u>Area of triangle ABD</u>

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(9-5)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

<u>Area of triangle BCD</u>

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(5-1)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

The area of the figure is

$12\ units^{2}+12\ units^{2}=24\ units^{2}$

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+AD$

we have

$A(-5,1),B(-8,5),C(-5,9),D(-2,5)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units$

Find the distance BC

$d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units$

Find the distance CD

$d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units$

Find the distance AD

$d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units$

substitute the values

$P=5+5+5+5=20\ units$

7 0

3 years ago