Y = 2x + 3
y = 2(3) + 3
y = 6 + 3
y = 9
Refer to the attached image.
Given the rectangle ABCD of length 'l' and height 'h'.
Therefore, CD=AB = 'l' and BC = AD = 'h'
We have to determine the area of triangle AEF.
Area of triangle AEF = Area of rectangle ABCD - Area of triangle ADF - Area of triangle ECF - Area of triangle ABE
Area of triangle ADF = 
= 
= 

Area of triangle ECF = 
= 
= 

Area of triangle ABE = 
= 
= 

Now, area of triangle AEF =
Area of rectangle ABCD - Area of triangle ADF - Area of triangle ECF - Area of triangle ABE
= 
= 
=
=

= 27 units
Therefore, the area of triangle AEF is 27 units.
Answer: X = 12.1 units
Step-by-step explanation:
Solving the side x of the triangle just requires the Pythagorean theorem.
x^2 + 7^2 = 14^2
x^2 + 49 = 196
subtract 49 on both sides, to cancel the 49 on the left side.
x^2 = 147 units
extract the square root of each side.
X = 12.1 units
Hope I Helped!
A solution possible for that can be n=25-14,,,therefore n=11....