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Yuki888 [10]
3 years ago
5

What’s the distance between (3.5, 1) and (-4, 2.5)

Mathematics
1 answer:
murzikaleks [220]3 years ago
7 0

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

distance =  \sqrt{ ({ - 4 - 3.5})^{2} +  ({2.5 - 1})^{2}  }  \\

distance =  \sqrt{ ({7.5})^{2} +  ({1.5})^{2}  }  \\

distance =  \sqrt{56.25 + 2.25}

distance =  \sqrt{58.5}

distance = 7.648

distance = 7.65

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

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valina [46]
Part A.

Consider a punch containing L liters.

60% of these that is \frac{60}{100}L=0.6L is grape juice, and the rest, 0.4 L is lemon-soda.

so, for the variable L, the total amount of punch, the total amount of grape juice is 0.6 L
and the amount of lemon soda in the punch is 0.4L
 
Part B.

For L=2, we substitute and get:

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4 years ago
Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

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Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

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Answer:

Step-by-step explanation:

two step equation

n - 5/2 = 5

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n = 7.5

-----------

check

7.5 - 5/2 = 5

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Step-by-step explanation:

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