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Lera25 [3.4K]
3 years ago
5

What's 221 rounded to the nearest 10

Mathematics
1 answer:
ycow [4]3 years ago
4 0
It would be 220 rounded to the nearest ten because the number in the ones place does not equal or exceed 5. 

So 220 is your answer :)
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(-3/4m)-(1/2)=2+(1/4,)
Aleks [24]
(-3/4m) -(1/2)=2+(1/4m)
-(1/2)=2+m
m= -3/2
5 0
3 years ago
What is 1 plus 2 plus 3.... plus 200?
Aneli [31]

Answer:

20100

Step-by-step explanation:

There are 200 numbers in this addition problem. To add this, we can do 1 + 200, 2 + 199, 3 + 198 and so on. All of these pairs have a sum of 201 and since there are 200 / 2 = 100 pairs the answer is 201 * 100 = 20100.

6 0
3 years ago
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An insurance company has 25,000 automobile policy holders. If the yearly claim of a policy holder is a random variable with mean
telo118 [61]

Answer:

P(T>8300000)=1-P(T

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Data given

n = 25000 represent the automobile policy holders

\mu= 320 represent the population mean

\sigma =540 represent the population standard deviation

Let T the variable that represent the total of interest on this case. We can assume that the random variable for an individual policy holder is given by:

X\sim N(\mu = 540, \sigma=540)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

First we need to find the distribution for the random variable T like this:

\bar X = \frac{\sum_{i=1}^n x_i}{n}

And the total T is given by:

T=\sum_{i=1}^n X_i =n \bar X

We can find the expected value, variance and deviation for this random variable like this:

E(T)= n E(\bar X) = n \mu = 25000*320=8000000

Var(T)= Var(n\bar X)= n^2 Var(\bar X) = n^2 \frac{\sigma^2}{n}=n \sigma^2 =25000*(540^2)=7290000000

Sd(T)=\sqrt{7290000000}=85381.497

And we are interested on this probability:

P(T>8300000)

And we can use the Z score formula given by:

Z=\frac{T-E(T)}{\sigma_T}

P(T>8300000)=1-P(T

6 0
3 years ago
On a timed session please help I have one more question after this.....
olya-2409 [2.1K]

The coffee shop used 52 pounds of Type A coffee.

Step-by-step explanation:

Cost of Type A coffee per pound = 5.25

Cost of Type B coffee per pound = 4.10

Total pounds used in blend = 142

Total cost = 642.00

Let,

x be the pounds of Type A coffee used

y be the pounds of Type B coffee used

According to given statement;

x+y=142      Eqn 1

5.25x+4.10y=642.00   Eqn 2

Multiplying Eqn 1 by 4.10

4.10(x+y=142)\\4.10x+4.10y=582.20\ \ \ Eqn\ 3

Subtracting Eqn 3 from Eqn 2

(5.25x+4.10y)-(4.10x+4.10y)=642.00-582.20\\5.25x+4.10y-4.10x-4.10y=59.80\\1.15x=59.80\\

Dividing both sides by 1.15

\frac{1.15x}{1.15}=\frac{59.80}{1.15}\\x=52\\

The coffee shop used 52 pounds of Type A coffee.

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/10677255
  • brainly.com/question/10689103

#LearnwithBrainly

5 0
3 years ago
Find the slope of the line containing the points (6,4) and (6,8)
kramer

Answer:

Undefined.

Step-by-step explanation:

Note that the x-coordinate does not change.  This indicates that the two points lie on a vertical line.  The slope of a vertical line is undefined.


6 0
3 years ago
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