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PSYCHO15rus [73]
3 years ago
6

What is the sum of 8/11 and 1/2?

Mathematics
2 answers:
natita [175]3 years ago
7 0

Answer:

27/22 or 1 5/22

bonufazy [111]3 years ago
4 0

Answer:

17/22

Step-by-step explanation:

8/11+1/2=16/22+11/22=17/22

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7 times a number is 8 less than the square of that number. Find the negative solution.
charle [14.2K]

Answer:

  -1

Step-by-step explanation:

The required relation is ...

  7n = n^2 -8

  0 = n^2 -7n -8 . . . . put in standard form

  0 = (n -8)(n +1) . . . . factor

Solutions are n=8 and n=-1.

The negative solution is -1.

7 0
3 years ago
What can i do to inprove my math skills
myrzilka [38]

Answer:

Practice, study, get involved in school activities involving math, don’t get too stressed out when it doesn't work, and always try again.

7 0
2 years ago
Read 2 more answers
the height h(t) of a trianle is increasing at 2.5 cm/min, while it's area A(t) is also increasing at 4.7 cm2/min. at what rate i
nekit [7.7K]

Answer:

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

Step-by-step explanation:

From Geometry we understand that area of triangle is determined by the following expression:

A = \frac{1}{2}\cdot b\cdot h (Eq. 1)

Where:

A - Area of the triangle, measured in square centimeters.

b - Base of the triangle, measured in centimeters.

h - Height of the triangle, measured in centimeters.

By Differential Calculus we deduce an expression for the rate of change of the area in time:

\frac{dA}{dt} = \frac{1}{2}\cdot \frac{db}{dt}\cdot h + \frac{1}{2}\cdot b \cdot \frac{dh}{dt} (Eq. 2)

Where:

\frac{dA}{dt} - Rate of change of area in time, measured in square centimeters per minute.

\frac{db}{dt} - Rate of change of base in time, measured in centimeters per minute.

\frac{dh}{dt} - Rate of change of height in time, measured in centimeters per minute.

Now we clear the rate of change of base in time within (Eq, 2):

\frac{1}{2}\cdot\frac{db}{dt}\cdot h =  \frac{dA}{dt}-\frac{1}{2}\cdot b\cdot \frac{dh}{dt}

\frac{db}{dt} = \frac{2}{h}\cdot \frac{dA}{dt} -\frac{b}{h}\cdot \frac{dh}{dt} (Eq. 3)

The base of the triangle can be found clearing respective variable within (Eq. 1):

b = \frac{2\cdot A}{h}

If we know that A = 130\,cm^{2}, h = 15\,cm, \frac{dh}{dt} = 2.5\,\frac{cm}{min} and \frac{dA}{dt} = 4.7\,\frac{cm^{2}}{min}, the rate of change of the base of the triangle in time is:

b = \frac{2\cdot (130\,cm^{2})}{15\,cm}

b = 17.333\,cm

\frac{db}{dt} = \left(\frac{2}{15\,cm}\right)\cdot \left(4.7\,\frac{cm^{2}}{min} \right) -\left(\frac{17.333\,cm}{15\,cm} \right)\cdot \left(2.5\,\frac{cm}{min} \right)

\frac{db}{dt} = -2.262\,\frac{cm}{min}

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

6 0
3 years ago
. At Carmi’s Pizza, 8% of the pizzas made last week had mushrooms. If 30 pizzas had mushrooms, how
I am Lyosha [343]

Answer:

b 375

Step-by-step explanation:

6 0
3 years ago
Solve 50q-43=52q-81
ladessa [460]
Move the variables to one side and the constants to the other

50q - 43 = 52q - 81

50q (-52q) - 43 (+43) = 52q (-52q) - 81 (+43)

50q - 52q = -81 + 43

-2q = -38

isolate the q, divide -2 from both sides

-2q/-2 = -38/-2

q = -38/-2

q = 19

hope this helps
8 0
4 years ago
Read 2 more answers
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