Answer:
2y² + 9
---------------
15y³
Step-by-step explanation:
Start by identifying the LCD, and then change each fraction so that its denominator is the LCD.
Here the LCD is 15y³, which is evenly divisible by 15y and 5y³.
Focus now on the first fraction: 2 / (15y). Multiplying numerator and denominator of this fraction by y² results in
y²·2 2y²
--------- → ----------
y²·15y 15y³ ←This is the correct LCD
Multiplying numerator and denominator of the second fraction by 3 results in:
3·3 9
------------ → ---------
3·5y³ 15y³ ←This is the correct LCD
So now those two original terms look like:
2y² 9
--------- + --------
15y³ 15y³
and this can be written in simpler form as:
2y² + 9
---------------
15y³
If 5x - 17 ≥ 0, then |5x - 17| = 5x - 17 and the equation reduces to
-8 - 2 (5x - 17) = -14
-8 - 10x + 34 = -14
-10x = -40
x = 4
If 5x - 17 < 0, then |5x - 17| = -(5x - 17) = -5x + 17 and we have
-8 - 2 (-5x + 17) = -14
-8 + 10x - 34 = -14
10x = 28
x = 2.8
False, since all sides are equal all angles must be equal and when you have an obtuse or right triangle only on angle is obtuse or right. since one is different it cannot be equal on all sides making this statement false
Answer:
∠Q = 75°
Step-by-step explanation:
Start by recognizing that the triangle is isosceles (the long sides are marked as being equal-length). That means angles Q and R have the same measure.
Next, you use the fact that the sum of angles is 180° to write an equation.
∠R +∠P +∠Q = 180°
(2x +15)° +x° +(2x +15)° = 180° . . . . substitute the known values
5x +30 = 180 . . . . . . . . . . . . . . . . divide by °, collect terms
5x = 150 . . . . . . . . subtract 30
x = 30 . . . . . . . divide by 5
Then angle Q is ...
∠Q = (2x +15)° = (2×30 +15)°
∠Q = 75°
- <em>0</em><em>.</em><em>0</em><em>0</em><em>5</em><em> </em><em><u>></u></em><em><u> </u></em><em> </em><em>0</em><em>.</em><em>0</em><em>5</em>
<h2><em>hope </em><em>it</em><em> helps</em><em>!</em></h2>
