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Nitella [24]
3 years ago
11

Use the quadratic formula to find the solutions to the quadratic equation below. 2x^2-5x+5=0

Mathematics
2 answers:
Alik [6]3 years ago
8 0

Answer:

5±i√15  /4

5 plus or minus i radical 15 over 4

Step-by-step explanation:

apex

Harrizon [31]3 years ago
3 0

Answer:

Step-by-step explanation:

So just plug in your numbers!

x = \frac{5±\sqrt{5^{2}-4*2*5 } }{2*2}

Ignore the A -- artifact of typesetting

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There are two ways to do this but the way I prefer is to make one of the equations in terms of one variable and then 'plug this in' to the second equation. I will demonstrate

Look at equation 1, -2x+y=10 this can quite easily be manipulated to show y=10+2x.

Then because there is a y in the second equation (and both equations are simultaneous) we can 'plug in' our new equation where y is in the second one 4x-y=-14 \Rightarrow 4x-(10+2x)=-14 which can then be solved for x since there is only one variable 4x-10-2x=-14 \Rightarrow 2x=-4 \Rightarrow x=-2 and then with our x solution we can work out our y solution by using the equation we manipulated y=10+2x = 10+(2 \times -2) = 10-4=6.

So the solution to these equations is x=-2 when y=6
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Step-by-step explanation:

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