Use the quadratic formula to find the solutions to the quadratic equation below. 2x^2-5x+5=0

Mathematics

2 answers:

Alik [6]3 years ago

8 0

Answer:

5±i√15 /4

5 plus or minus i radical 15 over 4

Step-by-step explanation:

apex

Harrizon [31]3 years ago

3 0

Answer:

Step-by-step explanation:

So just plug in your numbers!

$x = \frac{5±\sqrt{5^{2}-4*2*5 } }{2*2}$

Ignore the A -- artifact of typesetting

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20. Solve for x when 18x = 2/3 Provide your answer as a fraction. please do not do website

serious [3.7K]

18x/18 = 2/3 • 18
Flip reciprocal of 18 which is 1/18 so it would be 2/3 • 1/18 the 2 and 18 can be simplified when cross multiples so it would then be 1/3 • 1/9 which is x=1/27

3 0

3 years ago

E=VIT how would I isolate the “V” variable

Zigmanuir [339]

Answer:

$V =\frac{E}{IT}$

Step-by-step explanation:

You can isolate the "V" variable by dividing by IT on both sides:

$\frac{E}{IT} =\frac{VIT}{IT}$

On the left, the IT from the top and bottom cancel, leaving you with just V:

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6 0

3 years ago

Y= -27(x+4)³+1 the real zero(s) is (are)

rjkz [21]

$\bf y=-27(x+4)^3+1\implies 0=-27(x+4)^3+1
\\\\\\
-1=-27(x+4)^3\implies \cfrac{-1}{-27}=(x+4)^3\implies \cfrac{1}{27}=(x+4)^3
\\\\\\
\sqrt[3]{\cfrac{1}{27}}=x+4\implies \cfrac{\sqrt[3]{1}}{\sqrt[3]{27}}=x+4\implies \cfrac{1}{3}=x+4\implies \cfrac{1}{3}-4=x
\\\\\\
-\cfrac{11}{3}=x$