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Nitella [24]
3 years ago
11

Use the quadratic formula to find the solutions to the quadratic equation below. 2x^2-5x+5=0

Mathematics
2 answers:
Alik [6]3 years ago
8 0

Answer:

5±i√15  /4

5 plus or minus i radical 15 over 4

Step-by-step explanation:

apex

Harrizon [31]3 years ago
3 0

Answer:

Step-by-step explanation:

So just plug in your numbers!

x = \frac{5±\sqrt{5^{2}-4*2*5 } }{2*2}

Ignore the A -- artifact of typesetting

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8 of 10
Naya [18.7K]

Answer:

2.

Step-by-step explanation:

To find the answer, we take Gordon's result, 3, and subtract 2, which is what he added to get 3. This gives us a result of 1. We then multiply by 2, as 1 was the quotient of dividing the original number by 2. This leaves us with an answer of 2.

7 0
3 years ago
Evaluate the limit with either L'Hôpital's rule or previously learned methods.lim Sin(x)- Tan(x)/ x^3x → 0
Vsevolod [243]

Answer:

\dfrac{-1}{6}

Step-by-step explanation:

Given the limit of a function expressed as \lim_{ x\to \ 0} \dfrac{sin(x)-tan(x)}{x^3}, to evaluate the following steps must be carried out.

Step 1: substitute x = 0 into the function

= \dfrac{sin(0)-tan(0)}{0^3}\\= \frac{0}{0} (indeterminate)

Step 2: Apply  L'Hôpital's rule, by differentiating the numerator and denominator of the function

= \lim_{ x\to \ 0} \dfrac{\frac{d}{dx}[ sin(x)-tan(x)]}{\frac{d}{dx} (x^3)}\\= \lim_{ x\to \ 0} \dfrac{cos(x)-sec^2(x)}{3x^2}\\

Step 3: substitute x = 0 into the resulting function

= \dfrac{cos(0)-sec^2(0)}{3(0)^2}\\= \frac{1-1}{0}\\= \frac{0}{0} (ind)

Step 4: Apply  L'Hôpital's rule, by differentiating the numerator and denominator of the resulting function in step 2

= \lim_{ x\to \ 0} \dfrac{\frac{d}{dx}[ cos(x)-sec^2(x)]}{\frac{d}{dx} (3x^2)}\\= \lim_{ x\to \ 0} \dfrac{-sin(x)-2sec^2(x)tan(x)}{6x}\\

=  \dfrac{-sin(0)-2sec^2(0)tan(0)}{6(0)}\\= \frac{0}{0} (ind)

Step 6: Apply  L'Hôpital's rule, by differentiating the numerator and denominator of the resulting function in step 4

= \lim_{ x\to \ 0} \dfrac{\frac{d}{dx}[ -sin(x)-2sec^2(x)tan(x)]}{\frac{d}{dx} (6x)}\\= \lim_{ x\to \ 0} \dfrac{[ -cos(x)-2(sec^2(x)sec^2(x)+2sec^2(x)tan(x)tan(x)]}{6}\\\\= \lim_{ x\to \ 0} \dfrac{[ -cos(x)-2(sec^4(x)+2sec^2(x)tan^2(x)]}{6}\\

Step 7: substitute x = 0 into the resulting function in step 6

=  \dfrac{[ -cos(0)-2(sec^4(0)+2sec^2(0)tan^2(0)]}{6}\\\\= \dfrac{-1-2(0)}{6} \\= \dfrac{-1}{6}

<em>Hence the limit of the function </em>\lim_{ x\to \ 0} \dfrac{sin(x)-tan(x)}{x^3} \  is \ \dfrac{-1}{6}.

3 0
3 years ago
Does the order of information matter when writing a proof? (geometry)
n200080 [17]

Answer:

Yes it does matter

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
What is the median of the data set? {17, 40, 23, 44, 44, 30} Enter your answer in the box.
beks73 [17]
To find the median of the data set, we must first order them from lowest to highest in increasing order. Let's rearrange them in that way:

{17, 23, 30, 40, 44, 44}

Then we begin by crossing one off from each side, until we get to the middle. However, we see that our middle here is both 30 and 40.

What we do in a case like this is add up the two numbers and divide by 2 (essentially find the mean of the two middlemost numbers). Let's do that now:

30+40=70

\frac{70}{2}=35

So now we know that the median of the set of data is 35.
8 0
3 years ago
What is the slope of points (4,9) (-8,-6)? ​
12345 [234]

Answer:

5/4

Step-by-step explanation:

(y₂ - y₁) / (x₂ - x₁)

(4,9) (-8, -6)

plug in

(-6 - 9) / (-8 - 4)

solve within parentheses

-15/-12

simplify

5/4

6 0
3 years ago
Read 2 more answers
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