The answer is going to be
X=20
The solution is:A mole of gas occupies 22.4 L A liter is 1000 cubic centimeters because 1 cubic centimeter = 1 mL
One Helium molecule (essentially one helium atom) has atomic mass 4 g/mol So for every 22400 cubic centimeters of volume, we have 4 grams of helium Density of helium = 4g / 22400 cm^3 = 1g / 5600 cm^3
Volume of a sphere = (4/3)(pi)r^3 Volume of the outside sphere (the entire sphere) is (4/3)(pi)(R+T)^3 Volume of the inside sphere (the hollow region) is (4/3)(pi)R^3
The difference for the volume of silver. (4/3)(pi)(R+T)^3 - (4/3)(pi)R^3 = (4/3)(pi)(3R^2T + 3RT^2 + T^3)
The density of silver is 10.5g/cm^3
So the mass of the silver is computed by:10.5*(4/3)(pi)(3R^2T + 3RT^2 + T^3) = (14*pi)(3R^2T + 3RT^2 + T^3) = (14pi)T(3R^2 + 3RT + T^2)
Now for the mass of helium: volume x density = (4/3)(pi)R^3 (1/5600) = (pi/4200)R^3
Set the two masses equal: (pi/4200)R^3 = (14pi)T(3R^2 + 3RT + T^2) R^3 = 58800*T(3R^2 + 3RT + T^2) R / T = 58800*(3R^2 + 3RT + T^2) / R^2 = 58800*( 3+T/R^2+(T/R)^2)
then solve for xx = T / R 1/x = 58800*( 3+x/R+x^2) 1/58800 = x (3 + x/R + x^2) 1/58800 = 3x + x^3 x^3 + 3x - 1/58800= 0 x = ~ 5.66893x10^(-6)
Answer:
Option D
Step-by-step explanation:
Given expression has been given as,
![\sqrt[5]{224x^{11}y^8}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B224x%5E%7B11%7Dy%5E8%7D)
![\sqrt[5]{224x^{11}y^8}=\sqrt[5]{2\times 2\times 2\times 2\times 2\times 7(x^{11})(y^8)}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B224x%5E%7B11%7Dy%5E8%7D%3D%5Csqrt%5B5%5D%7B2%5Ctimes%202%5Ctimes%202%5Ctimes%202%5Ctimes%202%5Ctimes%207%28x%5E%7B11%7D%29%28y%5E8%29%7D)
![=\sqrt[5]{(2^5)\times (7)(x^{10}\times x)(y^5\times y^3)}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B5%5D%7B%282%5E5%29%5Ctimes%20%287%29%28x%5E%7B10%7D%5Ctimes%20x%29%28y%5E5%5Ctimes%20y%5E3%29%7D)
![=2x^2y\sqrt[5]{7xy^3}](https://tex.z-dn.net/?f=%3D2x%5E2y%5Csqrt%5B5%5D%7B7xy%5E3%7D)
Option D will be the answer.
Answer:
uhm
Step-by-step explanation:
Answer:
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