For midsegment theorem
And parallels lune are twice
So AB = YZ /2
AB = 10/2 =5
BUT AB = X–1 =5
X–1 = 5 = X = 1+5 =6
X =;6
..
MARK AS Brainliest
The area of the shaded sector is one-fourth of the area of the whole circle so:

area of shaded region

The area of the shaded region is 9pi units^2
im pretty sure the answer is 0.7

=3
r=common ratio: 12/6=2; 6/3=2
r=2,

=

*3
plug in 12 for n:

=
*3

=

*3

=2048*3

=6144
The twelfth term in the sequence is 6144
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