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Phantasy [73]
2 years ago
9

Twenty words were randomly selected from two textbooks. Each set gives the number of letters in each of the twenty words for tha

t textbook.
Briefly describe how the word lengths compare between textbook 2 and textbook 1.



Briefly describe the variability in the length of words in textbook 2 compared to textbook 1. PLEASE HURRY :(
Mathematics
1 answer:
Alborosie2 years ago
7 0

Answer:

k = 13The smallest zero or root is x = -10

Step-by-step explanation:

you can write "x^2" to mean "x squared"

f(x) = x^2+3x-10

f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5

f(x+5) = (x^2+10x+25)+3(x+5)-10

f(x+5) = x^2+10x+25+3x+15-10

f(x+5) = x^2+13x+30

Compare this with x^2+kx+30 and we see that k = 13

Factor and solve the equation below

x^2+13x+30 = 0

(x+10)(x+3) = 0

x+10 = 0 or x+3 = 0

x = -10 or x = -3

The smallest zero is x = -10 as its the left-most value on a number line.

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A vector with magnitude 9 points in a direction 190 degrees counterclockwise from the positive x axis. Write in component form
Over [174]

Answer:

\vec{v}= \text{ or } \approx

Step-by-step explanation:

Component form of a vector is given by \vec{v}=, where i represents change in x-value and j represents change in y-value. The magnitude of a vector is correlated the Pythagorean Theorem. For vector \vec{v}=, the magnitude is ||v||=\sqrt{i^2+j^2.

190 degrees counterclockwise from the positive x-axis is 10 degrees below the negative x-axis. We can then draw a right triangle 10 degrees below the horizontal with one leg being i, one leg being j, and the hypotenuse of the triangle being the magnitude of the vector, which is given as 9.

In any right triangle, the sine/sin of an angle is equal to its opposite side divided by the hypotenuse, or longest side, of the triangle.

Therefore, we have:

\sin 10^{\circ}=\frac{j}{9},\\j=9\sin 10^{\circ}

To find the other leg, i, we can also use basic trigonometry for a right triangle. In right triangles only, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse of the triangle. We get:

\cos 10^{\circ}=\frac{i}{9},\\i=9\cos 10^{\circ}

Verify that (9\sin 10^{\circ})^2+(9\cos 10^{\circ})^2=9^2\:\checkmark

Therefore, the component form of this vector is \vec{v}=\boxed{}\approx \boxed{}

6 0
3 years ago
PLEASE HELP
Mumz [18]
If you use/make a number line, then you will see that the answer is -18 or a. When using a number line, negative = ← and positive = →.
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3 years ago
(20 points) Simplify The Expression with work/steps<br><br> (8+3i) + (-2+ i)
zimovet [89]

Given the expression (8+3i)+(-2+i)

We need to simplify it.

(8+3i)+(-2+i)

First we have to remove the parenthesis.

8+3i-2+i

As we know that multiplication of positive and negative is negative.

Now we will add or subtract like terms. Like terms means here i with i and constant term with constant term. So here we will add 3i and i. Also subtract 2 from 8.

8-2 +3i+i

6+4i

We have got the required answer.

The simplified answer is 6+4i.

6 0
3 years ago
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