$\text{The minute hand of a clock is 9 inches long.}\\
\text{we need to find the distance traveled by the tip of the minute }\\
\text{hand moved in 40 minutes.}$

$\text{That is we need to find the length of the arc formed by the minute}\\
\text{hand in 40 minutes. We know that in one complete revolution of the}\\
\text{minute hand there are 60 minutes. so the central angle formed by the }\\
\text{minute hand in 40 minutes is}=\frac{40}{60}*2\pi =\frac{4\pi}{3} \text{ radians}\\
\\
\text{hence using the arc length formula, }s=r\theta, \text{ we get}\\
\\
\text{distance traveled by the tip}=9\times \frac{4\pi}{3}=12\pi\approx 37.7 \text{ inches}$

Hence the tip of the minute hand moved approximately 37.7 inches in 40 minutes.

5 0

3 years ago

What does 7/12 - 2/5 =

katen-ka-za [31]

The LCD here is 12(5) = 60.
We must rewrite <span>7/12 - 2/5 with 60 as common denominator.
Doing this, we get 35/60 - 24/60 = 11/60 (answer)</span>

6 0

3 years ago