Answer:
(t^2 -4) (t^2 +4)
(t-2)(t+2)(t^2+4)
Step-by-step explanation:
t^4 - 16
We can write this as the difference of squares
We know the dfference of squares is
(a^2 - b^2) = (a-b) (a+b)
( t^2 ^2 - 4^2) = (t^2 -4) (t^2 +4)
We can write t^2 -4 as the difference of squares
t^2 -4 = t^2 -2^2 = (t-2)(t+2)
Replacing this in
( t^2 ^2 - 4^2) = (t^2 -4) (t^2 +4) = (t-2)(t+2)(t^2+4)
Answer:
it is B i thinkif im wrong im sorry
Step-by-step explanation:
Answer:
When the shape reflects about the x-axis, the x-coordinate remains unchanged but the y-coordinate becomes negative. When the shape reflects about the y-axis, the y-coordinate remains the same but the x-coordinate becomes negative.
Step-by-step explanation:
Sample answer from Edmentum
24
It goes into 24 once and into 48 twice
<h3>
Answer: -6, 7, -8</h3>
Start with the sequence {1, 2, 3, 4, 5, 6, 7, 8, ...}
Then change the sign of every other term so you'll have the first term positive, the second term negative, and so on.
That updates to {1, -2, 3, -4, 5, -6, 7, -8, ...}
Every odd term (1,3,5,..) is positive while every even term (-2,-4,-6) is negative.
