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sesenic [268]
3 years ago
12

Evaluate. Round to the nearest tenth

Mathematics
1 answer:
Dima020 [189]3 years ago
6 0
Apply log rules

log_b(1) = 0

So

log_{12}(1)=0
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Which statement is correct for the graph of the specified function?
mash [69]

The correct statement regarding the function plotted in the graph is:

C) The maximum value of the quadratic function occurs at y = 4.

<h3>What is the rate of change of the linear function?</h3>

When x = 0, y = -7, and when x = -5, y = 8, hence the rate of change(change in y divided by change in x) is given by:

R = [8 - (-7)]/-5 - 0 = 15/-5 = -3

<h3>What is the maximum value of the quadratic function?</h3>

It is concave down, hence it has only a maximum value at y = 4 and not a minimum value, hence option C is correct.

More can be learned about functions at brainly.com/question/25537936

4 0
3 years ago
Find the value of x.
Marrrta [24]
<h3>Answer: 14</h3>

================================

Explanation:

The two angles shown are a linear pair. They are adjacent and supplementary.

Supplementary angles add to 180

(8x+1) + (4x+11) = 180

8x+1+4x+11 = 180

(8x+4x) + (1+11) = 180

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12x+12-12 = 180-12 ... subtract 12 from both sides

12x = 168

12x/12 = 168/12 ... divide both sides by 12

x = 14

8 0
3 years ago
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Farmer Ted bales large round bales of hay to store in his barn for winter feeding. How much hay is in a round bale, in terms of
umka21 [38]

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3 years ago
Find the area of the trapezoid<br> 3cm, 3cm, 8cm
love history [14]

The area of the trapezoid is the amount of space on it, and the value of the area is 16.5 square cm

<h3>How to determine the area?</h3>

The given parameters are:

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Area = 0.5 * (Sum of parallel sides) * Height

So, we have:

Area = 0.5 * (3 + 8) * 3

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Area = 16.5

Hence, the area of the trapezoid is 16.5 square cm

Read more about areas at:

brainly.com/question/24487155

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7 0
2 years ago
Find the endpoint of the line segment with the given endpoint and midpoint.
Luba_88 [7]
Answer: (-4, -7)

I dont know how to explain how I got that but I recommend using an app called Desmos. :)
5 0
3 years ago
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