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Papessa [141]
3 years ago
12

Write three multiplication equations in which the product will have two zerosUse 50 as one of the factors

Mathematics
1 answer:
Yuliya22 [10]3 years ago
4 0
1) 50 × 2 = 100
2) 60×20= 1200
3) 70×20=1400


Hope this helps
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A culture started with 4,000 bacteria. After 2 hours it grew to 4400 bacteria. Predict how many bacteria will be present after 1
Art [367]
 <span>idk why they want the dratted "k" . it is so simple w/o it ! 
in the form y = ab^x, a = 4000, b = 4400/4000 = 1.1, x = t/2 
N = 4000*1.1^(13/2) = 7432 <------ 
----------------- 
now you won't be satisfied with simplicity, so 
4400 = 4000e^2k 
e^2k = 1.1 
k = ln 1.1/2 = .0477 to 4 dp 
N(13) = 4000e^(13*.0477) = 7436 <------ 

note that apart from a roundabout way, you get a less accurate ans !</span>
5 0
3 years ago
Read 2 more answers
Just help me out with this polynomial i need help <br> { -m^{2} + 6} + { -4m^{2} + 7m + 2} =
PolarNik [594]

Answer:

-5m^2+7m+8

Step-by-step explanation:

Here, we add up two polynomials shown.

The polynomials are:

[-m^2 + 6]+[-4m^2 +7m + 2]

In order to add up the 2 polynomials shown, we have to see the "like terms" and add them up.

We add up the "m^2" terms and the constant (number) terms. There is one term with "m", so we leave it like that. Let's add up. Shown below:\

[-m^2 + 6]+[-4m^2 +7m + 2]\\=-m^2-4m^2+6+2+7m\\=-5m^2+7m+8

This is the sum of the 2 polynomials shown:  -5m^2+7m+8

7 0
3 years ago
Which equation is represented by the graph below?
dalvyx [7]

Where is the graph?

7 0
4 years ago
5y + 3 &gt; −7y + 13 Multi-step linear inequalities
Artemon [7]

Answer:

y > \frac{5}{6}

Step-by-step explanation:

Given

5y + 3 > - 7y + 13 ( add 7y to both sides )

12y + 3 > 13 ( subtract 3 from both sides )

12y > 10 ( divide both sides by 12 )

y > \frac{10}{12} , that is

y > \frac{5}{6}

3 0
3 years ago
Find the gradients of lines A and B.
Tanya [424]

Let's see

For line A

  • (2,2)
  • (3,6)

Slope

  • m=6-2/3-2
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For line B

  • (1,6)
  • (2,4)

Slope

  • m=4-6/2-1
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3 0
2 years ago
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