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3 years ago

How many groups of 60 equal 300

1 answer:

3 0

Okay, ask yourself this : how many times does 6 goes into 30?

6 and 1 = 6
6 and 2 = 12
6 and 3 = 18
6 and 4 = 24
6 and 5 = 30

6 goes into 30 a number of 5 times. And so that means that :

60 and 1 make 60.
60 and 2 make 120
60 and 3 make 180.
60 and 4 make 240
60 and 5 make 300

FIVE (5) groups of 60 make 300.

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The figure shows two triangles on a coordinate grid:

Firdavs [7]

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Nitric acid (specific gravity 1.42) costs $51.95 per liter. A student spills 5.112 kg of nitric acid in the laboratory, what is

Leno4ka [110]

Answer:

The cost of wasted nitric acid is $187.02

Step-by-step explanation:

Since it is given that specific gravity of Nitric Acid is 1.42 Thus the density of nitric acid is

$\rho _{acid}=S.G\times \rho _{water}\\\\\\\rho_{acid}=1.42\times 1\frac{g}{cm^3}\\\\\rho_{acid}=1.42g/cm^3$

Now from the basic relation of mass volume and density we have

$\rho =\frac{Mass}{Volume}\\\\\therefore Volume=\frac{Mass}{\rho }$

Since the mass of the nitric acid is given to be 5.112 kg = 5112 grams

Thus the volume of nitric acid is

$Volume=\frac{5112}{1.42}=3600cm^3$

Now we know that 1000 cubic centimeters euals 1 litrer

Thus the calculated volume in liters is

$V_{liters}=\frac{3600}{1000}=3.6Liters$

Thus the cost of acid spilled equals

$Cost=3.6\times 51.95=187.02$

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3 years ago

What is the equation in point-slope form of the line passing through (4, 0) and (2, 6)? (5 points) y = 4x − 2 y = 2x − 4 y = −3(

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For this case we have that by definition, the point-slope equation of a line is given by:

$y-y_ {0} = m (x-x_ {0})$

We have the following points:

$(x_ {1}, y_ {1}) :( 2,6)\\(x_ {2}, y_ {2}) :( 4,0)\\m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {0-6} {4-2} = \frac {-6} {2} = -3$

We chose a point:

$(x_ {0}, y_ {0}) :( 4,0)$

Substituting in the equation we have:

$y-0 = -3 (x-4)\\y = -3 (x-4)$

Finally, the equation is: $y = -3 (x-4)$

Answer:

OPTION C

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3 years ago

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Differentiate Functions of Other Bases In Exercise, find the derivative of the function.

WARRIOR [948]

Answer:

$\dfrac{dy}{dx} =\dfrac{2 x + 6}{ \log{\left (10 \right )}\left(x^{2} + 6 x\right)}$

Step-by-step explanation:

given

$y = \log_{10}{(x^2+6x)}$

using the property of log $\log_ab=\frac{log_cb}{log_ca}$ , and if c = $e$ , $\log_ab=\frac{ln{b}}{ln{a}}$ , we can rewrite our function as:

$y = \dfrac{\ln{\left (x^{2} + 6 x \right )}}{\ln{\left (10 \right )}}$

now we can easily differentiate:

$\dfrac{dy}{dx} = \dfrac{1}{\ln{10}}\left(\dfrac{d}{dx}(\ln{(x^{2} + 6x)})\right)$

$\dfrac{dy}{dx} = \dfrac{1}{\ln{10}}\left(\dfrac{2x+6}{x^{2} + 6x}\right)$

$\dfrac{dy}{dx} =\dfrac{2 x + 6}{ \log{\left (10 \right )}\left(x^{2} + 6 x\right)}$

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The answer is 80!!!!!!!!

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