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Nady [450]
3 years ago
10

Sherri sells photos of athletes to baseball, basketball, and hockey fans after their games. Her regular price is $10 per photogr

aph, and she usually sells about 30 photographs. Sherri finds that, for each reduction in price of $0.50, she can sell an additional two photographs
Mathematics
1 answer:
Tcecarenko [31]3 years ago
8 0

Answer:

so whats the question

Step-by-step explanation:

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Find the missing height of the cone. Volume= 118π ft3 Diameter= 2/3
grin007 [14]

Answer:

11 ft

Step-by-step explanation:

The equation for the volume of a cone is:

V = 1/3(3.14)r^2h

V = 414.48

r = 6

Plug in those values and solve for h:

414.48 = 1/3(3.14)(6)^2h

414.48 = 37.68h ; divide both sides by 37.68

11 = h

The missing height is 11ft.

6 0
3 years ago
Help me plzzzzzzzzzzzzzz ​
AVprozaik [17]
Y is 83° and x is 14°
3 0
2 years ago
Renee is playing a game with marbles and a spinner. The spinner has four sections: orange, black, purple, and white. The marbles
cestrela7 [59]

Answer:

i think 3 out of 4 chances

Step-by-step explanation:

because theyre are three colors alike, black, orange and purple.

4 0
3 years ago
Read 2 more answers
HELP PLEAE GIVING BRAINLIEST! MEAN A LOT IF YOU HELP! :)<br> HELP SOLVE
Bumek [7]

Answer:

160

Step-by-step explanation:

Muliply both sides by 20/3 to get e=20/3*24=160

5 0
3 years ago
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The distance of a golf ball from the hole can be represented by the right side of a parabola with vertex (-1,8). The ball reache
ddd [48]

Answer:

Let's suppose that the hole is at y = 0m, where x is the time variable.

we know that:

The vertex is (-1s, 8m).

(i suppose x in seconds and y in meters)

At x = 1s, the ball reaches the hole, so we also have the point:

(1s, 0m).

Remember that the vertex of a quadratic equation y = a*x^2 + b*x + c is at:

x = -b/2a,

then we have:

-1 = -b/2a.

Then we have tree equations:

8m = a*(-1s)^2 + b*-1s + c

0m = a*(1s)^2 + b*1s + c

-1s = -b/2a.

First we should isolate one variable in the third equation, and then replace it in one of the other two:

1s*2a = b.

So we can replace b in the first two equations bi 1s*2a.

8m = a*1s^2 - 1s*2a*1s + c

0m = a*1s^2 + 1s*2a*1s + c

We can simplify both equations and get:

8m = a*( 1s^2 - 2s^2) + c = -a*1s^2 + c.

0m = a*(1s^2 + 2s^2) + c = a*3s^2 + c.

Easily we can isolate c in the second equation and then replace it into the first equation:

c = -a*3s^2

The first equation becomes:

8m = -a*1s^2 - a*3s^2 = -a*4s^2

a = 8m/-4s^2 = -2m/s^2.

Now with a, we can find the values of c and b.

c = -a*3s^2 = -(-2m/s^2)*3s^2 = 6m.

b = 1s*2a = 1s*(-2m/s^2) = -2m/s.

Then the equation is:

y = (-2m/s^2)*t^2 + (-2m/s)*t + 6m

5 0
3 years ago
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