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malfutka [58]
3 years ago
5

I need help on this question. thank you​

Mathematics
1 answer:
ANTONII [103]3 years ago
8 0
The answer is 2 units long.
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Plz Hurry! Find the equivalent for -(3)^-4.<br>​
shepuryov [24]

Answer:

-1 ( 1/3*1/3*1/3*1/3)

Step-by-step explanation:

-(3)^-4

The exponent is only affecting what is inside the parentheses

-1 * (3) ^-4

We know that a^-b = 1/a^b

-1 * 1/3^4

-1/3^4

-1 ( 1/3*1/3*1/3*1/3)

8 0
4 years ago
What is the simplified value of the expression below?<br> –8*(-3) <br> -24<br> -11<br> 11<br> 24
LenKa [72]

The answers 24

Hope this helped.

3 0
4 years ago
A hyperbola centered at the origin has verticies at (add or subtract square root of 61,0 and foci at (add or subtract square roo
deff fn [24]

Answer:

\frac{x^2}{61}-\frac{y^2}{37}  =1

Step-by-step explanation:

The standard equation of a hyperbola is given by:

\frac{(x-h)^2}{a^2} -\frac{(y-k)^2}{b^2} =1

where (h, k) is the center, the vertex is at (h ± a, k), the foci is at (h ± c, k) and c² = a² + b²

Since the hyperbola is centered at the origin, hence (h, k) = (0, 0)

The vertices is (h ± a, k) = (±√61, 0). Therefore a = √61

The foci is (h ± c, k) = (±√98, 0). Therefore c = √98

Hence:

c² = a² + b²

(√98)² = (√61)² + b²

98 = 61 + b²

b² = 37

b = √37

Hence the equation of the hyperbola is:

\frac{x^2}{61}-\frac{y^2}{37}  =1

6 0
3 years ago
Hi I really need help with this assignment plz
brilliants [131]

the first option is the correct one


6 0
3 years ago
Read 2 more answers
On his first day of school, Kareem found the high temperature in degrees Fahrenheit to be 76.1°. He plans to use the function to
Alexandra [31]
24.5 Celsius. 
<span>
</span>The temperature t in degreen Celsius is equal to the temperature T in the degrees Fahrenheit minus 32, times 5/9
3 0
3 years ago
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