All categories

4 years ago

How to solve 4+|7-m|=5

1 answer:

4 0

When
|a|=b
assume
a=b and -a=b
so

4+|7-m|=5
minus 4 from both sides
|7-m|=1
assume
7-m=1 and
-(7-m)=1

7-m=1
minus 7 both sidees
-m=-6
times -1 both sides
m=6

-(7-m)=1
distribute
-7+m=1
add 7 to both sides
m=8

m=6 and 8

You might be interested in

Plz help asap <br> x + 10 = 20 and<br> y – 8 = 32<br> with step by step explanation plz

valentina_108 [34]

Answer:

10 & 40

Step-by-step explanation:

x+10=20------------------10-20=10

y-8=32--------------------32+8=40

3 0

3 years ago

Graph the line that passes through the two lines (1,5/2), (-1/2,-1/4)

mars1129 [50]

Answer:

Step-by-step explanation:

7 0

3 years ago

When do we say information is valuable?

solmaris [256]

Every piece of information, public or not, has a value to somebody

6 0

3 years ago

If 1 yard=3 feet and 1 mile=5,280 feet, how many yards are there in 2 miles

posledela

2 miles equals 2 x1760 = 3520 yards.

3 0

4 years ago

Read 2 more answers

Laundry detergent boxes are filled according to an approximately Normal distribution with mean 34.15 ounces and standard deviati

Leno4ka [110]

Using the normal distribution, it is found that there is a 0.0668 = 6.68% probability a randomly selected box has less than the 34 ounces of advertised weight.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 34.15, \sigma = 0.1$ .

The probability a randomly selected box has less than the 34 ounces of advertised weight is the <u>p-value of Z when X = 34</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{34 - 34.15}{0.1}$

Z = -1.5

Z = -1.5 has a p-value of 0.0668.

0.0668 = 6.68% probability a randomly selected box has less than the 34 ounces of advertised weight.

More can be learned about the normal distribution at brainly.com/question/24537145

#SPJ1

7 0

2 years ago