All categories

2 years ago

Please help!!!!.................,

Mathematics

1 answer:

dangina [55]2 years ago

5 0

Answer:

I think it's 45 lmk if I'm wrong lol

You might be interested in

What is the square root of -1

Zinaida [17]

Answer:

Step-by-step explanation:

square root of -1 is i

6 0

3 years ago

Read 2 more answers

PLEASE HELP I WILL GIVE BRAINLIEST

OLga [1]

Answer:

$67

Step-by-step explanation:

So 5x12+7=C

PEDMAS so:

5x12 = 60

60+7 = 67

67 = C

8 0

2 years ago

What 5 divided by 475

Nataly [62]

Answer:

it's 0.01 (approx.)

Step-by-step explanation:

brainliest plz

8 0

2 years ago

Read 2 more answers

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

My name is Ann [436]

$x = 2 \\ y = 7$

is the answer to:

$y = 11 - 2x \\ 4x - 3y = - 13$

_________________________________________

$x = 5 \\ y = 2$

is the answer to:

$2x + y = 12 \\ x = 9 - 2y$

_________________________________________

$x = 3 \\ y = 5$

is the answer to:

$2x + y = 11 \\ x - 2y = - 7$

_________________________________________

$x = 7 \\ y = 3$

is the answer to:

$x + 3y = 16 \\ 2x - y = 11$

3 0

3 years ago

The midpoint of AB is at (3,7) and A is at (0,-5). Where is B located?

olga nikolaevna [1]

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ \square }}\quad ,&{{ \square }})\quad 
% (c,d)
&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)\qquad thus
\\
----------------------------\\$ $\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ 0}}\quad ,&{{ -5}})\quad 
% (c,d)
B&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
% coordinates of midpoint 
(3,7)\impliedby midpoint\qquad thus
\\ \quad \\
\left(\cfrac{{{ x_2 }} + {{ 0}}}{2}=3\quad ,\quad \cfrac{{{ y_2 }} + {{( -5)}}}{2}=7 \right)\to 
\begin{cases}
\cfrac{{{ x_2 }} + {{ 0}}}{2}=3
\\ \quad \\
\cfrac{{{ y_2 }} + {{ -5}}}{2}=7
\end{cases}
\\ \quad \\
solve\ for\ x_2\ and\ y_2$

3 0

2 years ago