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vovangra [49]
4 years ago
6

the average speed of car #1 is 35 mph and the average speed of car #2 is 55 mph. time elapsed between start of car #1 and start

of car #2 is 18 minutes. How long before car #2 takes over car #1?
Mathematics
1 answer:
nadezda [96]4 years ago
4 0
Are there any answer choices?
You might be interested in
Please help extra points and Mark bring list
Nady [450]

answer: dividing the number by 100

100 ×100= 100000

100000÷100

100

5 0
3 years ago
Simplify the following expressions
qaws [65]

Answer:

1. -15c - 4

2. 3x - 5

3. 14q

4. -195 + 39m

5. 55b + 130

Step-by-step explanation:

6 0
2 years ago
Consider the set whose elements are the graphs having vertex set {1, 2, 3, 4}, and consider the relation on that set, where two
Damm [24]

Answer:

7

Step-by-step explanation:

Let S be the set of all graphs having vertex set  \{1,2,3,4\}. The relation \rho is defined over S such that

the graphs G and H are equivalent provided that they have same number of edges. Then, the number of equivalence classes depends on how many edges can be there in the vertex set \{1,2,3,4\} .

The number of edges is 0 forms a disconnected graph which makes an equivalent class.

The graphs of 1 edge makes an equivalent class.

The graphs of 2 edges makes an equivalent class.

The graphs of 3 edges makes an equivalent class.

The graphs of 4 edges makes an equivalent class.

The graphs of 5 edges makes an equivalent class.

In similar way, the only graph of 6 edges is complete graph which forms another equivalent class.

Hence,the total number of equivalent classes is 7.

8 0
3 years ago
Can someone please help me work out this question i really don't understand ​
nadya68 [22]

Answer:

108 cm^2

Step-by-step explanation:

rectangle   + 2  triangle = total area

L x W          + 2    *  1/2 base * height   = total area

(5x12)          + 2    *  1/2 * 12 * 4    = total area

  60              +   48    = 108 cm^2

7 0
2 years ago
Read 2 more answers
The polynomial of degree 4, P ( x ) has a root of multiplicity 2 at x = 4 and roots of multiplicity 1 at x = 0 and x = − 4 . It
Annette [7]

Answer: P(x) = {(x-4)^2} (x) (x+4)

Step-by-step explanation:

Let's start with the multiplicity of 2;

At multiplicity of 2; x=4.

Therefore, x - 4 is a factor of the function P(x).

Since it has a multiplicity of 2, we will rewrite the factor as (x-4)^2

Now for the multiplicity of 1.

At this multiplicity of 1, x= 0 and - 4.

Therefore, the factors are x-0 and x+4

Since multiplicity of 1, the factors remain as they are without any additional root on top.

Therefore, the factors of the polynomial p(x) are (x-4)^2 and x and x+4.

And solution of P(x) in factor form will be: P(x) = {(x-4)^2} (x) (x+4)

7 0
3 years ago
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