Suppose that the exchange rate from U.S. dollars to Canadian dollar is 1 U.S. dollar per 1.0028 Canadian dollars. Joey exchanges
1 answer:
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Answer:
D) 191
Step-by-step explanation:
The entire circle is 254.5, calculated by using this formula
Only 3/4 of the circle is needed for the area, however, so you multiply your area by 0.75
Answer:
the diagonal measurement from corner A to corner B=15 inches
Step-by-step explanation:
as we know that the loptop has the shape of a rectangle that means all it's angles are right angles. so we can use the pythogoras theorem to find out the diagonal of the rectangle.
let us denote the diagonal of rectangle by D and the sides of rectangle be denoted by X=12 and Y=9
so by using pythogoras theorem we have,
=225
D=15
Hence the diagonal measurement from corner A to corner B is 15 inches.
Answer:
4x+12
Step-by-step explanation:
Answer: p = 0.9337
Step-by-step explanation: from the question, we have that
total number of pen (n)= 15
number of pen that has never been used=9
number of pen that has been used = 15 - 9 =6
number of pen choosing on monday = 3
total number of pen choosing on tuesday=3
note that the total number of pen is constant (15) since he returned the pen back .
probability of picking a pen that has never been used on tuesday = 9/15 = 3/5
probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5
probability of picking a pen that has been used on tuesday = 6/15 = 2/5
probability of not picking a pen that has not been used on tuesday= 1- 2/5= 3/5
on tuesday, 3 balls were chosen at random and we need to calculate the probability that none of them has never been used .
we know that
probability of ball that none of the 3 pen has never being used on tuesday = 1 - probability that 3 of the pens has been used on tuesday.
to calculate the probability that 3 of the pen has been used on tuesday, we use the binomial probability distribution
p(x=r) =
n= total number of pens=15
r = number of pen chosen on tuesday = 3
p = probability of picking a pen that has never been used on tuesday = 9/15 = 3/5
q = probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5
by slotting in the parameters, we have that
p(x=3) =
p(x=3) = 455 *
p(x=3) = 455 * 0.064 * 0.002176
p(x=3) = 0.0633
thus probability that 3 of the pens has been used on tuesday. = 0.0633
probability of ball that none of the 3 pen has never being used on tuesday = 1 - 0.0633 = 0.9337