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2 years ago

Nathan invested $80,000 in an account paying an interest rate of 6% compounded

Mathematics

1 answer:

bija089 [108]2 years ago

8 0

Answer:

Number of year = 13 year and 6 month approx.

Step-by-step explanation:

Given:

Amount invested = $80,000

Rate of interest = 6% compounded continuously

Future value of investment = $175,600

Find:

Number of year

Computation:

Future value of investment = Amount invested[1 + Rate of interest]ⁿ

175,600 = 80,000[1+6%]ⁿ

175,600 = 80,000[1+0.06]ⁿ

175,600 = 80,000[1.06]ⁿ

Number of year = 13.492 year

Number of year = 13 year and 6 month approx.

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180-37-22=121
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(sin 121)/4.357=(sin 22)/a
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a= (4.356× sin22) /(sin 121)

type in the calculator to find what is a.

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3 years ago

Robert used 34 grams of iron filings in his second experiment. This is 16 grams more than twice the number of grams he used in h

sweet-ann [11.9K]

34=2x + 16

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Robert used 9 grams of iron filings in his first experiment.

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3 years ago

What is the equation of the line that passes through the point (8,-3) and has an undefined slope?

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Answer:

x = 8

Step-by-step explanation:

A line with "undefined" slope is a vertical line, whose equation is of the form ...

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In order for the line to go through a point with an x-coordinate of 8, the constant must be 8.

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8 0

3 years ago

1011+111 in binary form

Ann [662]

Answer:

10010

Step-by-step explanation:

$1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$111=1(2)^2+1(2)^1+1(2)^0$

So $1011+111$ gives us:

$1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$+$

$1(2)^2+1(2)^1+1(2)^0$

-----------------------------------------------------

Combine like terms:

$1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0$

$1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0$

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace $2^0$ with 1 and $2$ with $(2)^1$ :

$1(2)^3+1(2)^2+(2)^2+(2)^1(1)$

I want a $2^0$ number:

$1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0$

Combine like terms:

$1(2)^3+2(2)^2+1(2)^1+0(2)^0$

$2(2)^2=2^3$ :

$1(2)^3+2^3+1(2)^1+0(2)^0$

Combine like terms:

$2(2)^3+1(2)^1+0(2)^0$

We can rewrite the first term by law of exponents:

$2^4+1(2)^1+0(2)^0$

$1(2)^4+1(2)^1+0(2)^0$

So the binary form is:

$10010$

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

1 0 1 1

+ 1 1 1

------------------------------

(1) (1) (1)

1 0 1 1

+ 1 1 1

------------------------------

1 0 0 1 0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0

3 years ago

A number of friends decided to go on a picnic and planned to spend rs. 96 on eatables. four of them, however, did not turn up. a

mr Goodwill [35]

The number of those who attended the picnic was 8.

Quadratic equations are the polynomial equations of degree 2 in one variable of type f(x) = $ax^{2} + bx + c$ = 0 where a, b, c, ∈ R and a ≠ 0.

Such questions are best examples of quadratic equations where the unknown is simply assumed to be a variable which when substituted according to the conditions yield a quadratic equation which can easily be solved.

Let x represent the whole population.

Total Spending = Rs. 96

Thus, each individual's contribution is equal to 96/x.

Four people did not show up causing

others to contribute Rs. 4 extra.

So the given condition can be written as

96/(x-4) – 96/x = 4

=>96x – 96(x-4) = 4x(x-4)

=> 96x -96x + 384 = 4x2 – 16x

=> 4x2 – 16x – 384 = 0

=> x2 – 4x – 96 = 0

=> (x – 12)(x + 8) = 0

=> x = 12 or x = -8 (neglect)

So x = 12

x-4 = 8 ( because four of them did not turn up)

∴ The number of those who attended the picnic was 8.

Learn more about quadratic equations here :

brainly.com/question/15241362

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2 years ago