Answer:
<u>ALTERNATIVE 1</u>
a. Find the profit function in terms of x.
P(x) = R(x) - C(x)
P(x) = (-60x² + 275x) - (50000 + 30x)
P(x) = -60x² + 245x - 50000
b. Find the marginal cost as a function of x.
C(x) = 50000 + 30x
C'(x) = 0 + 30 = 30
c. Find the revenue function in terms of x.
R(x) = x · p
R(x) = x · (275 - 60x)
R(x) = -60x² + 275x
d. Find the marginal revenue function in terms of x.
R'(x) = (-60 · 2x) + 275
R'(x) = -120x + 275
The answers do not make a lot of sense, specially the profit and marginal revenue functions. I believe that the question was not copied correctly and the price function should be p = 275 - x/60
<u>ALTERNATIVE 2</u>
a. Find the profit function in terms of x.
P(x) = R(x) - C(x)
P(x) = (-x²/60 + 275x) - (50000 + 30x)
P(x) = -x²/60 + 245x - 50000
b. Find the marginal cost as a function of x.
C(x) = 50000 + 30x
C'(x) = 0 + 30 = 30
c. Find the revenue function in terms of x.
R(x) = x · p
R(x) = x · (275 - x/60)
R(x) = -x²/60 + 275x
d. Find the marginal revenue function in terms of x.
R(x) = -x²/60 + 275x
R'(x) = -x/30 + 275
Answer:
Commitment Adherence Percentage = 81.
%
Step-by-step explanation:
The time period Amy scheduled herself, t = 8 a.m. - 1 p.m. from Sunday through Wednesday
The period she released her interval = 11 a. m. - 1 p.m.
Commitment Adherence Percentage = Service Minutes/(Posted Minutes + Released Lockdown Minutes) × 100
Posted minutes = 5 hours/day × 60 minutes × 4 days = 1200 minutes
Serviced minute = 5 hours/day × 60 minutes × 3 days + 3 hours × 60 minutes/hour = 1,080 minutes
Released minutes = 2 hours × 60 minutes/hour = 120 minutes
Commitment Adherence Percentage = (1,080/(1,200 + 120)) × 100 = 81.%
I think you need to provide what A is in order to solve that
Answer:
it would take 3/5 of an hour or 0.6 as a decimal
Step-by-step explanation:
3 3/4 divided by 2 1/4 is 3/5 or 0.6
Hope this helped!
A=.5(h)(b)
A=.5(8)(14
A=4(14)
A=56 cm^2
