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2 years ago

9

A line connects points A and B ( -5,5 and -5,-3) as shown below. If a third point, C, is plotted six units to the right of point

B, what will be the area of the resulting right triangle?

2 answers:

Strike441 [17]2 years ago

8 0

1,5 is the answer my guy!

katrin2010 [14]2 years ago

7 0

You will get this easily by putting it on a real graph which should help u get the answer by plugging the points in

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Express the fraction 3/4, 7/16 and 5/8 with the LCD

____ [38]

12/16, 7/16, 10/16 (not simplified, just with LCD);The LCD of the 3 fractions is 16 (from denominators) so all we have to do is multiply both the numerator by the same number that multiplies with the denominators to get 16. We leave 7/16 alone since it already has denominator of 16.

3/4 * 4 = 12/16

5/8 * 2 = 10/16

3 0

3 years ago

1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)

Sveta_85 [38]

Answer:

1. $-5x+3y+44=0$

2. $2x+y-2=0$

3. $2x+y-4=0$

Step-by-step explanation:

Standard form of a line is $Ax+By+C=0$ .

If a line passing through two points then the equation of line is

$y-y_1=m(x-x_1)$

where, m is slope, i.e., $m=\dfrac{y_2-y_1}{x_2-x_1}$ .

1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

$y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)$

$y+3=\dfrac{-5}{-3}(x-7)$

$y+3=\dfrac{5}{3}(x-7)$

$3(y+3)=5(x-7)$

$3y+9=5x-35$

$-5x+3y+9+35=0$

$-5x+3y+44=0$

Therefore, the required equation is $-5x+3y+44=0$ .

2.

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to $2 x + y =-5$ .

Slope of the line : $m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2$

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

$y-2=-2(x-0)$

$y-2=-2x$

$2x+y-2=0$

Therefore, the required equation is $2x+y-2=0$ .

3.

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to $2x + y =-5$ .

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

$y-0=-2(x-2)$

$y=-2x+4$

$2x+y-4=0$

Therefore, the required equation is $2x+y-4=0$ .

5 0

2 years ago

Which term describes a system with exactly one solution

vlada-n [284]

It is called a consistent dependent system

7 0

2 years ago

The equation of a line is y=-2.5x+3. Which one of these points lies on this line?

lakkis [162]

D is the correct answer. Since this is an equation, equation means both side are equal. So if you put each point in place of y and x and do the math on the left side, the final result of that side has to be equal to the left one. Only (-2,2) follows this statement aka its a point on this line .

7 0

3 years ago

I will give brainliest if correct

dalvyx [7]

Answer:supplementary

Step-by-step explanation:

Opposite angles in any quadrilateral inscribed in a circle are supplements of each other.

5 0

3 years ago