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Kisachek [45]
3 years ago
13

How can an individual find career data?

Computers and Technology
1 answer:
kolezko [41]3 years ago
6 0
How can an individual find career data?a. using a libraryb. searching the webc. conducting an interview with someone in a particular fieldd. all answer choices are sources for finding career data?The answer is d. An individual can do all the option a, b, and c to find a better career data.
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Sanjay is giving a slideshow presentation on his entire college class and he is feeling quite nervous in order to share his pres
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I think that would be the (HDD) Hard Disk Drive! Hope this helps!
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3 years ago
Select the best answer from the drop-down menu.
maw [93]

Answer:

1) performance assessments

2) measurable goals

3)can't be measured quantitatively

4) milestones

Explanation:

Methods of evaluating the performance and productivity of an individual or group in relation to predetermined criteria and measurable goals are <u>performance assessments.</u>

<u>measurable goals</u> are goals that have concrete criteria for measuring progress toward their attainment.

Why are statements like “great customer experience” or “more sales” not good assessment criteria? <u>can't be measured quantitatively</u>

Personal goal setting helps lagging performance by setting <u>milestones</u>

which are short-term achievable tasks.

<u>OAmalOHopeO</u>

8 0
3 years ago
Read 2 more answers
The _____ feature automatically corrects typing, spelling, capitalization, or grammar errors as you type them.
Snezhnost [94]
Autocorrect is the answer
6 0
3 years ago
A raised dot (ú) shows where the ENTER key was pressed. <br> a. True<br> b. False
MatroZZZ [7]
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5 0
3 years ago
Add each element in origList with the corresponding value in offsetAmount. Print each sum followed by a space. Ex: If origList =
Darya [45]

Answer:

#include <stdio.h>

int main(void) {

const int NUM_VALS = 4;

int origList[NUM_VALS];

int offsetAmount[NUM_VALS];

int i;

origList[0] = 20;

origList[1] = 30;

origList[2] = 40;

origList[3] = 50;

offsetAmount[0] = 5;

offsetAmount[1] = 7;

offsetAmount[2] = 3;

offsetAmount[3] = 4;

for(i=0;i<NUM_VALS;i++)

{

printf("%d ",origList[i]+offsetAmount[i]);

}

printf("\n");

return 0;

}

Explanation:

  • Initialize the origList and offsetAmount variables.
  • Loop up to the value of NUM_VALS variable.
  • Display the output by combining origList and offsetAmount.
5 0
3 years ago
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