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juin [17]
3 years ago
5

You are training to complete in a local 5K run. You record your time scores in minutes after completing seven practice runs. Wri

te a method to calculate and return the average score based on the data.
Computers and Technology
1 answer:
trapecia [35]3 years ago
3 0

Answer:

Following are the program to this question:

#include <iostream>//defining header file

using namespace std;

float Avg(float sum, int n)//defining method Avg that accepts float parameter

{

float average=sum/n;//defining float variable average that holds average value  

return average;//return average

}

int main()//defining main method

{

float ar[ ] = {24.1,24.5,24.4,23.8,28.2,29.1,27.4};//defining float array

float sum;//defining float variable sum

int n=7,i;//defining integer variable  

for (i = 0; i <n; i++)//defining loop to count total of array

{

sum=sum+ar[i];//add value in sum variable

}

cout<<"The average is: "<<Avg(sum,n);//use print method to call and print method return value

return 0;

}

Output:

The average is: 25.9286

Explanation:

In the above code, the float method "Avg" is declared, that accepts two parameters, that is "sum and n", inside the method, a float variable average is declared that divides and returns its values.

In the main method a float array "ar" is declared that holds values, in the next line, float variable "sum" and integer variable "n, j" is used.

In for loop, the "i" variable is used to add array values in the sum variable and pass into cout to call the "Avg" method and print its return value.

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You are given a string of n characters s[1 : : : n], which you believe to be a corrupted text document in which all punctuation
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Answer: provided in the explanation section

Explanation:

Given that:

Assume D(k) =║ true it is [1 : : : k] is valid sequence  words or false otherwise

  • To determine D(n)

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So, from here we have that D(k) is given by the following recorance relation:

D(k) = ║ false maximum (d[l]∧DICT(s[1 + 1 : : : k]) otherwise

Algorithm:

Valid sentence (s,k)

D [1 : : : k]             ∦ array of boolean variable.

for a ← 1 to m

do ;

d(0) ← false

for b ← 0 to a - j

for b ← 0 to a - j

do;

if D[b] ∧ DICT s([b + 1 : : : a])

d (a) ← True

(b). Algorithm Output

      if D[k] = = True

stack = temp stack           ∦stack is used to print the strings in order

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Use JavaWrite a program that will simulate a change machine found at cash registers. Input the amount due and amount paid from t
Ksju [112]

Answer:

Here is the JAVA program:

import java.util.Scanner;  //to accept input from user

public class Main { // class name

 public static void main(String [] args) {  // start of main method

   Scanner input = new Scanner(System.in);  // creates Scanner class object to take input from user

   System.out.println("Please Enter the Cost of the Item: ");  // prompts user to enter the cost of item

   double itemCost = input.nextDouble();  //scans and reads the input value of item cost

   System.out.println("Please Enter the Amount Paid: ");  // prompts user to enter the amount paid

   double amount = input.nextDouble();  //scans and reads the value of amount from user

   int change = (int)(amount * 100 - itemCost * 100);  //compute the remaining amount i.e. change

   System.out.println("Change Owed: " + change / 100.0);  // displays the owed change

   int quarters = change / 25;  // computes the value for quarters

   change = change % 25;  // compute the quarters remaining

   int dimes = change / 10;  //  computes dimes

   change = change % 10;  //  computes dimes remaining

   int nickels = change / 5;  // computes nickels

   change = change % 5;  // compute nickels remaining

   int pennies = change;  // computes pennies

   System.out.println("Quarters: " + quarters);  // displays computed value of quarters

   System.out.println("Dimes: " + dimes);  // displays value of dimes

   System.out.println("Nickels: " + nickels);  // displays value of nickels

   System.out.println("Pennies: " + pennies);   }} //displays value of pennies

Explanation:

I will explain the program with an examples.

Suppose the user enters 4.57 as cost of the item and 5.00 as amount paid. Then the program works as follows:

Change is computed as

change = (int)(amount * 100 - itemCost * 100);

This becomes;

change = (int)(5.00 * 100 - 4.57 * 100)

            = 500 - 457

change = 43

Now the change owed is computed as:

change / 100.0 = 43/100.0 = 0.43

Hence change owed = 0.43

Next quarters are computed as:

quarters = change / 25;

This becomes:

quarters = 43/25

quarters = 1

Now the remaining is computed as:

   change = change % 25;

This becomes:

   change = 43 % 25;

  change = 18

Next the dimes are computed from remaining value of change as:

dimes = change / 10;

dimes = 18 / 10

dimes = 1

Now the remaining is computed as:

   change = change % 10;

This becomes:

   change = 18 % 10

  change = 8

Next the nickels are computed from remaining value of change as:

nickels = change / 5;

nickels = 8 / 5

nickels = 1

Now the remaining is computed as:

   change = change % 5;

This becomes:

   change = 8 % 5

  change = 3

At last the pennies are computed as:

pennies = change;

pennies = 3

So the output of the entire program is:

Change Owed: 0.43                                                                                                                Quarters: 1                                                                                                                      Dimes: 1                                                                                                                         Nickels: 1                                                                                                                       Pennies: 3  

The screenshot of the output is attached.

7 0
3 years ago
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