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Semenov [28]
4 years ago
12

Please can someone help me

Mathematics
1 answer:
erik [133]4 years ago
4 0

36=2(x+6)

36=2x+12

-12=2x-12

24=2x

12=x

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3(2x + 6) - 4x = 2(5x - 2) + 6
sp2606 [1]

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Step-by-step explanation:

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lara31 [8.8K]
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5 0
3 years ago
Please help me with #'s 5&6
Fynjy0 [20]

5.\\(x+3)^2+7=-2\qquad|-7\\\\(x+3)^2=-9 < 0\\\\\text{NO REAL SOLUTION}\\\\(x+3)^2=-9\to x+3=\pm\sqrt{-9}\\\\x+3=-3i\ \vee\ x+3=3i\qquad|-3\\\\\boxed{x=-3-3i\ \vee\ x=-3+3i}

6.\\4(x-10)^2=25\qquad|:4\\\\(x-10)^2=\dfrac{25}{4}\to x-10=\pm\sqrt{\dfrac{25}{4}}\\\\x-10=-\dfrac{\sqrt{25}}{\sqrt4}\ \vee\ x-10=\dfrac{\sqrt{25}}{\sqrt4}\\\\x-10=-\dfrac{5}{2}\ \vee\ x-10=\dfrac{5}{2}\\\\x-10=-2.5\ \vee\ x-10=2.5\qquad|+10\\\\\boxed{x=7.5\ \vee\ x=12.5}

7 0
4 years ago
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