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4 years ago

Need help with 1 2 3 4 and 6 please need it for today

Mathematics

2 answers:

barxatty [35]4 years ago

4 0

Since you still need 3, this is the answer: 2/6, 2/4, 2/3

Irina18 [472]4 years ago

3 0

1. The answer is 20cm
2.The answer is 26cm.
6.Kg

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By paying $50 cash up front and the balance at $35 a

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26 weeks i think

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3 years ago

A) 93<br>B) 85<br>C) 107<br>D) 79

Alex787 [66]

D is the answer i think it is at least

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4 years ago

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Natasha_Volkova [10]

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3 years ago

Bill booked a ride to the airport. If it rains, the traffic will be bad and the probability that he will miss his flight is 0.06

kvasek [131]

Answer:0.614

Step-by-step explanation:

Given

Probability he will miss flight if it rains=0.06

Probability he will miss flight it does not rain=0.01

Given the probability of rain=0.21

Therefore Probability that it will not rain=1-0.21=0.79

Probability that he will miss the flight $=0.21\times 0.06+0.79\times 0.01=0.0205$

P(actual raining and he missed the flight| he miss the flight) $=\frac{0.21\times 0.06}{0.21\times 0.06+0.79\times 0.01}$

$=\frac{0.0126}{0.0205}=0.614$

7 0

3 years ago

Help plzzz thank you !

VashaNatasha [74]

Answer:

a. Ameribank-$15,157.50

b. Capital Two-$4,646.25

Step-by-step explanation:

a. Tad's savings is $15,000, we calculate his total amount at the end of the year for each bank:

#Ameribank

$A=P+I=P+PRT\\\\=15000+15000\times 0.0105\times 1\\\\=\$15,157.50$

#Huffington( we use the effective rate to calculate the compound amount):

$i_m=(1+i/m)^m-1\\\\=(1+0.0095/12)^[12}-1=0.009541\\\\A=P(1+i_m)^n\\\\=15000(1.009541)^1\\\\=\$15,143.12$

#Sixth-Third, Take 1 yrs=52 weeks:

$i_m=(1+i/m)^m-1\\\\=(1+0.01/52)^{52}-1=0.01005\\\\A=15000(1.01005)^1\\\\=\$15,150.74$

#Hence, Ameribank is the best option as his money grows to $15,157.50 which is greater than all the remaining two options.

b. We use the compound interest formula $A=P(1+r/n)^{nt}$ to determine which bank gives the best option:

#Capital Two. r=3.75%, n=12,t=4

$A=P(1+r/n)^{nt}\\\\=4000(1+0.0375/12)^{12\times4}\\\\=\$4,646.25$

#J.C Morgan, t=2, r=3.55% n=12

$A=P(1+r/n)^{nt}\\\\=4000(1+0.0355/12)^{12\times 2}\\\\=\$4,293.87$

#Silverman Slacks, n=12,t=3, r=3.65%

$A=P(1+r/n)^{nt}\\\\=4000(1+0.0365/12)^{12\times3}\\\\=\$4,462.14$

We compare the investment amounts after t years:

$Capital>Silver>Morgan=4646.25>4462.14>4293.87$

Hence, Capital two is the best option with an investment amount of $4,646.25

8 0

3 years ago

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