Answer:
Type right under my comment
Explanation:
Look in comments
Answer:
Check explanation
Explanation:
Two stacks can make use of one array by utilizing various stack pointers that begins from different ends of an array. Looking at the array A[1...
], the first stack will drive elements that starts from position 1 as well as to move its' pointer to .
The Second stack will begin at the position and motion its' pointer to 1. The best likely divide is to offer each stack a half of an array. whenever any of two stacks transverse the half-point, an overflow can happen but for that overall number of elements, it must be
Answer:
In Java:
import java.util.*;
public class Main{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String isbn;
System.out.print("First 1:2 digits: ");
isbn = input.nextLine();
if(isbn.length()==12){
int chksum = 0;
for(int i = 0; i<12;i++){
if((i+1)%2==0){ chksum+= 3 * Character.getNumericValue(isbn.charAt(i)); }
else{ chksum+=Character.getNumericValue(isbn.charAt(i)); } }
chksum%=10;
chksum=10-chksum;
if(chksum==10){
System.out.print("The ISBN-13 number is "+isbn+"0");}
else{
System.out.print("The ISBN-13 number is "+isbn+""+chksum); } }
else{
System.out.print("Invalid Input");
} }}
Explanation:
See attachment for explanation where comments are used to explain each line
JavaScript can be used to simulate the behavior of the placeholder attribute in older browsers by using the placeholder attribute which add a placeholder text as a default value and using a different color to differentiate from a color previously entered.
<h3>How are behavior simulated?</h3>
Normally, a user can simulate the behavior of placeholder text in older browsers by setting the value of the value property.
In conclusion, the JavaScript can be used to simulate the behavior of the placeholder attribute in older browsers by using the placeholder attribute which add a placeholder text as a default value and using a different color to differentiate from a color previously entered.
Raed more about JavaScript
<em>brainly.com/question/16698901</em>
