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Tom [10]
3 years ago
15

Original grade 80 New grade 100 Find the percent of increase

Mathematics
2 answers:
balandron [24]3 years ago
7 0

Answer:

hey eemack! your answer is wrong try again

Step-by-step explanation:

Taya2010 [7]3 years ago
4 0

Answer: 20% increase

Step-by-step explanation: It’s out of 100 and you first got 80 and then you got 100. Since it’s out of 100 you could just subtract to numbers ex: 100-80=20. The answer is 20% increase

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Suppose , varies jointly with g and v, and j = 2 when g = 4 and v= 3.
kap26 [50]

Answer:

j = 44/3

Step-by-step explanation:

j varies jointly as g and v. This can be represented mathematically as:

j \alpha gv\\j = kgv.............(1)

Where k is a constant of proportionality

j = 2 when g = 4 and v = 3

Substitute these values into equation (1)

2 = k * 4 * 3

2 = 12 k

k = 1/6

when g = 8 and v = 11:

j = (1/6) * 8 * 11

j = 44/3

7 0
3 years ago
How do i solve 6m_2=m+13
I am Lyosha [343]
If it's addition you do the opposite which is subtraction and that's the answer that you get so 6m_2=m+13 so add 6-2=4 and then 13-4=9
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2 years ago
6. If EF=3x-17, FG=2x-8, and EG=15, find the value of x, EF, and FG. the drawing is not to scale
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Don't trust those links, my guy it's a scam or virus
7 0
3 years ago
The hexagon GIKMPR and FJN are regular. The dashed line segments form 30 degree angles.
Cerrena [4.2K]
We know that for each triangle made up by dashed line segment forms 30° angles, so, for example, ∠GOH is 30° and then ∠HOI is 30°

Rotating the shape 240° around the centre is the same as counting in 30°

The triangle GOH will first fit the triangle HOI then triangle IOJ and so on until it has completed 8 times 30° turn. Its final position is shown in the diagram below

4 0
2 years ago
Read 2 more answers
Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calcul
Step2247 [10]
\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
A&({{ 6}}\quad ,&{{ 5}})\quad 
%  (c,d)
B&({{ x}}\quad ,&{{y}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
\textit{if the distance \underline{d} is 5, then }5=\sqrt{(x-6)^2+(y-5)^2}
7 0
3 years ago
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