Answer: (a) 0.006
(b) 0.027
Step-by-step explanation:
Given : P(AA) = 0.3 and P(AAA) = 0.70
Let event that a bulb is defective be denoted by D and not defective be D';
Conditional probabilities given are :
P(D/AA) = 0.02 and P(D/AAA) = 0.03
Thus P(D'/AA) = 1 - 0.02 = 0.98
and P(D'/AAA) = 1 - 0.03 = 0.97
(a) P(bulb from AA and defective) = P ( AA and D)
= P(AA) x P(D/AA)
= 0.3 x 0.02 = 0.006
(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)
= P(AA) x P(D/AA) + P(AAA) x P(D/AAA)
= 0.3(0.02) + 0.70(0.03)
= 0.027
75 - 18.5 = 56.5
the number is 56 1/2 or 56.5
Tracker B has a greater radius and would be able to cover more area.
<h3>
What is an Equation</h3>
An equation is an expression that is used to show the relationship between two or more numbers and variables.
Tracker A has a radius of 4.102 feet, hence:
Area covered = π * 4.102² = 52.86 ft²
Tracker B has a radius of 104 feet, hence:
Area covered = π * 104² = 33979.5 ft²
Tracker B has a greater radius and would be able to cover more area.
Find out more on Equation at: brainly.com/question/13763238
