Scale in terms of cm to m= 1/5
In every meter there are 5 cm
Considering this, if the dimensions are 15cm and 20cm, you would need to multiply them by 5 to convert them to meters
15*5= 75 20* 5=100
Dimensions- 75ft by 100ft
Answer:
La distancia de C con respecto a A es de 197.788 metros.
Step-by-step explanation:
A manera de imagen adjunta construimos una representación del enunciado del problema, la cual representa a un triángulo cuyos tres ángulos son conocidos y la longitud del segmento AB, medida en metros, son conocidos. Por medio de la Ley del Seno podemos calcular la longitud del segmento AC (distancia de C con respecto a A), medida en metros:
(1)
Si sabemos que 
, 
y 
, entonces la longitud del segmento AC es:
La distancia de C con respecto a A es de 197.788 metros.
one more point. because bobcats scored
14 and huskies scored 15
Unfortunately you have not included the directions. Are you supposed to solve for x? or for y?
Suppose the directions say, "Solve for x." Then, clear out the decimal fraction by mult. both sides of the given equation by 10. This will give you the solution, that is, a formula for x in terms of y.
Answer:
The linear equation in two variables is 5u - 8v = 150 .
Step-by-step explanation:
As given
The cost of 5 tables exceeds the cost of 8 chairs by Rs150 .
Let us assume that the cost of one table be u .
Let us assume that the cost of one chairs be v .
Than the equation becomes
5u + 150 = 8v
Simplify the above equation
5u - 8v = 150
Therefore the linear equation in two variables is 5u - 8v = 150 .
