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V125BC [204]
3 years ago
11

Solve 47 (math operation)

Mathematics
1 answer:
Alchen [17]3 years ago
8 0

Answer:

  t ≈ -2.014 or 3.647

Step-by-step explanation:

Add the opposite of the expression on the right side of the equal sign to put the equation into standard form.

  4.9t² -8t -36 = 0

You can divide by 4.9 to make this a little easier to solve.

  t² -(8/4.9)t -36/4.9 = 0

Now, add and subtract the square of half the x-coefficient to "complete the square."

  t² -(8/4.9)t +(4/4.9)² -36/4.9 -(4/4.9)² = 0

  (t -4/4.9)² -192.4/4.9² = 0 . . . . simplify

Add the constant term, then take the square root.

  (t -4/4.9)² = 192.4/4.9²

  t -4/4.9 = ±(√192.4)/4.9

  t = (4 ± √192.4)/4.9

  t ≈ {-2.014, 3.647}

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\mathbf a=\mathbf i-3\,\mathbf j+\mathbf k
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3 years ago
A train traveled 720km in 9h. How far would it travel in 11 hr? How long would it take to go 1120km?
kompoz [17]
It would go 880 km in 11 hours, and it would take 14 hours to go 1120 km
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2 years ago
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Suppose y varies inversely with x, and y=39 when x=1/3.what is the value of y when x=26
vagabundo [1.1K]

Answer:

y = 1/2

Step-by-step explanation:

Varies inversely

xy = k

------------------------

Find the constant of variation

y = 39 when x = 1/3

k = 1/3 * 39

k = 13

-----------------------

what is the value of y when x=26

26y = 13

y = 13/26

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6 0
2 years ago
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Hello I am really struggling on this test, can someone please help me and I will help you
olganol [36]

Answer:

x = 50

Step-by-step explanation:

SU is a midline segment and is one half the measure of VW, thus

VW = 2SU , that is

x - 46 = 2(x - 48) ← distribute

x - 46 = 2x - 96 ( subtract x from both sides )

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6 0
3 years ago
On Halloween, a man presents a child with a bowl containing eight different pieces of candy. He tells her that she may have thre
likoan [24]

Answer:

56 choices

Step-by-step explanation:

We know that we'll have to solve this problem with a permutation or a combination, but which one do we use? The answer is a combination because the order in which the child picks the candy <u><em>does not</em></u> matter.

To further demonstrate this, imagine I have 4 pieces of candy labeled A, B, C, and D. I could choose A, then C, then B or I could choose C, then B, then A, but in the end, I still have the same pieces, regardless of what order I pick them in. I hope that helps to understand why this problem will be solved with a combination.

Anyways, back to the solving! Remember that the combination formula is

_nC_r=\frac{n!}{r!(n-r)!}, where n is the number of objects in the sample (the number of objects you choose from) and r is the number of objects that are to be chosen.

In this case, n=8 and r=3. Substituting these values into the formula gives us:

_8C_3=\frac{8!}{3!5!}

= \frac{8*7*6*5*4*3*2*1}{3*2*1*5*4*3*2*1} (Expand the factorials)

=\frac{8*7*6}{3*2*1} (Cancel out 5*4*3*2*1)

=\frac{8*7*6}{6} (Evaluate denominator)

=8*7 (Cancel out 6)

=56

Therefore, the child has \bf56 different ways to pick the candies. Hope this helps!

3 0
3 years ago
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