Answer:
You have two sets of parallel sides. A square has two sets of parallel sides, and it has the extra condition that all of the angles are right angles. So a square is definitely going to be a rhombus. Now, all rhombuses have four sides.
Step-by-step explanation:
Answer: the statements and resons, from the given bench, that fill in the blank are shown in italic and bold in this table:
Statement Reason
1. K is the midpoint of segment JL Given
2. segment JK ≅ segment KL <em>Definition of midpoint</em>
3. <em>L is the midpoint of segment KM</em> Given
4. <em>segment KL ≅ segment LM</em> Definition of midpoint
5. segment JK ≅ segment LM Transitive Property of
Congruence
Explanation:
1. First blank: you must indicate the reason of the statement "segment JK ≅ segment KL". Since you it is given that K is the midpoint of segment JL, the statement follows from the very <em>Definition of midpoint</em>.
2. Second blank: you must add a given statement. The other given statement is <em>segment KL ≅ segment LM</em> .
3. Third blank: you must indicate the statement that corresponds to the definition of midpoint. That is <em>segment KL ≅ segment LM</em> .
4. Fourth and fith blanks: you must indicate the statement and reason necessary to conclude with the proof. Since, you have already proved that segment JK ≅ segment KL and segment KL ≅ segment LM it is by the transitive property of congruence that segment JK ≅ segment LM.
<h2>
Answer:</h2>
<u>First, Arrange the data in ascending order</u>
=> 18, 20, [21], 22, 23.
<u>Now, Find the middle term i.e, 21.</u>
<u>Hence, Median of the given data is 21</u>.
Answer:
Step-by-step explanation:
Calculus....finally something FUN to answer!
This is integration, but here you have the area under the curve, you just don't have the upper bound. Setting that problem up looks like this:
and using the First Fundamental Theorem of Calculus, that will integrate to look like this:
from 1 to b and applying the FTC:
Multiplying everything by 2 to get rid of the denominators gives you:
