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3 years ago

Three of the following steps are used in writing a mixed number as an improper fraction. Which step does NOT belong?

Mathematics

2 answers:

Mrac [35]3 years ago

8 0

Answer:

You don't divide the numerator by the denominator

Step-by-step explanation:

Mamont248 [21]3 years ago

8 0

Answer:

√ Write the mixed numbers as improper fractions.

√ Multiply the numerators to get 24.

√ Multiply the denominators to get 6.

√ Write the improper fraction as a mixed number.

√ The product is 4.

X The product is 2 and two-fifths.

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max is making a rectangular garden that is 5 feet less than twice its width. If the perimeter of the garden is 80 feet, what wil

djverab [1.8K]

L=2w-5

2(l+w)=80
l+w=40
2w-5+w=40
3w=45
w=15 feet
l=25 feet. As a result, the width is 15 feet and length is 25 feet. Hope it help!

7 0

2 years ago

Read 2 more answers

Write the equation of the line parallel to y=8x-1 that contains the point (-6,2)

Tasya [4]

Equation: y = 8x - 1
Compare it with, y = mx + b
Slope, m = 8
Now, parallel line must have equal slope, = 8

We know, y - y1 = m(x - x1)
y - 2 = 8(x + 6)

Hope this helps!

6 0

2 years ago

How do i solve this?

alina1380 [7]

Answer:

x=3

Step-by-step explanation:

minus 3x on both sides

after you've subtracted 3x from both sides you then need to minus 12 from both sides

Last step is going to be dividing by 2 and you should get the answer of 3

8 0

3 years ago

Read 2 more answers

Find the area and the circumference of a circle with the radius 3 ft.Use 3.14 for pi

Lilit [14]

ANSWER

• Circumference: 18.84 ft

• Area: 28.26 ft²

EXPLANATION

The circumference of a circle of radius r is,

$C=2\pi r$

In this case, the radius is r = 3 ft and we have to use 3.14 for π,

$C=2\cdot3.14\cdot3ft=18.84ft$

Hence, the circumference of this circle is 18.84 feet.

The area of a circle of radius r is,

$A=\pi r^2$

In this case, r = 3 ft and π = 3.14,

$A=3.14\cdot3^2ft^2=28.26ft^2$

Hence, the area of this circle is 28.26 square feet.

6 0

8 months ago

Find e^cos(2+3i) as a complex number expressed in Cartesian form.

ozzi

Answer:

The complex number $e^{\cos(2+31)} = \exp(\cos(2+3i))$ has Cartesian form

$\exp\left(\cosh 3\cos 2\right)\cos(\sinh 3\sin 2)-i\exp\left(\cosh 3\cos 2\right)\sin(\sinh 3\sin 2)$ .

Step-by-step explanation:

First, we need to recall the definition of $\cos z$ when $z$ is a complex number:

$\cos z = \cos(x+iy) = \frac{e^{iz}+e^{-iz}}{2}$ .

Then,

$\cos(2+3i) = \frac{e^{i(2+31)} + e^{-i(2+31)}}{2} = \frac{e^{2i-3}+e^{-2i+3}}{2}$ . (I)

Now, recall the definition of the complex exponential:

$e^{z}=e^{x+iy} = e^x(\cos y +i\sin y)$ .

So,

$e^{2i-3} = e^{-3}(\cos 2+i\sin 2)$

$e^{-2i+3} = e^{3}(\cos 2-i\sin 2)$ (we use that $\sin(-y)=-\sin y)$ .

Thus,

$e^{2i-3}+e^{-2i+3} = e^{-3}\cos 2+ie^{-3}\sin 2 + e^{3}\cos 2-ie^{3}\sin 2)$

Now we group conveniently in the above expression:

$e^{2i-3}+e^{-2i+3} = (e^{-3}+e^{3})\cos 2 + i(e^{-3}-e^{3})\sin 2$ .

Now, substituting this equality in (I) we get

$\cos(2+3i) = \frac{e^{-3}+e^{3}}{2}\cos 2 -i\frac{e^{3}-e^{-3}}{2}\sin 2 = \cosh 3\cos 2-i\sinh 3\sin 2$ .

Thus,

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)$

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right]$ .

5 0

2 years ago