X/2 +3y = 6 . . . . . . . . starting point
x/2 = 6 -3y . . . . . . . . subtract terms that don't have x
x = 2(6 -3y) . . . . . . . . multiply by the inverse of the x-coefficient
x = 12 -6y . . . . . . . . . expand if you like
3y = 6 -x/2 . . . . . . . . subtract terms that don't have y
y = (6 -x/2)/3 . . . . . . . multiply by the inverse of the y-coefficient
y = 2 -x/6 . . . . . . . . . expand if you like
Answer:
e and f
Step-by-step explanation:
I am talking to and idiot on the phone so i am dying of boredom
Answer: b = 40
sin B =
cos B =
tg B =
sec B =
csc B =
cot B =
Step-by-step explanation: If the right angle is at C, then the hypothenuse is side c = 41.
Using Pythagorean Theorem:
hypotenuse² = side² + side²
41² = 9² + b²
b =
b = 40
The side b length is <u>40</u>,
The trigonometric functions of a right triangle are:
1) Sine =
sin (B) =
Sin(B) =
2) Cosine =
cos (B) =
cos (B) =
3) Tangent =
tg (B) =
tg (B) =
4) Sec =
sec(B) =
sec(B) =
5) Cosecant =
csc(B) =
csc(B) =
6) Cotangent =
cot(B) =
cot(B) =
C = 5/9(F - 32)....when F = 32...so sub in 32 for F
C = 5/9(32 - 32)
C = 5/9(0)
C = 0
so at 32 F, it is 0 C