In a triangle, two sides that measure 8 centimeters and 11 centimeters form an angle that measures 82°. to the nearest tenth of
a degree, determine the measure of the smallest angle in the triangle.
1 answer:
We can use the Сosine formula to solve this problem.
<span>First we must find the third side (АС) of the triangle:
</span>
<span>
The smallest angle of the triangle lies opposite the smallest side, so we need to find m</span>∠C.
Now we can use Bradis's Table (I don't know the name in English, maybe Trigonometric Table?) to find m∠C:
m∠С = 38°42' = 38.7°
Answer: 38.7°
<span>I hope this helps</span>
<span>First we must find the third side (АС) of the triangle:
</span>
<span>
The smallest angle of the triangle lies opposite the smallest side, so we need to find m</span>∠C.
Now we can use Bradis's Table (I don't know the name in English, maybe Trigonometric Table?) to find m∠C:
m∠С = 38°42' = 38.7°
Answer: 38.7°
<span>I hope this helps</span>
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