Total Area<span>0.42*TotalArea = 5880 <span>Hence TotalArea = 5880/0.42 = 14000 sq ft </span></span>
Answer:
m=2
b=1
y=2x+1
Step-by-step explanation:
slope is change in y over change in x, or rise over run. Plugging these points in, (y2-y1)/(x2-x1)=(1--5)/(0--3), or 6/3, simplifying, the slope= 2.
Next, the y-intercept is where the line intersects the y-axis, or when x is 0. Looking at the point (0,1), the y intercept is 1.
Using slope intercept form, y=mx+b, or y=2x+1.
To find the greatest common factor (it should be divisor) of an expression, you have to take the smallest power of each letter and the smallest power of each prime number that the two expressions have in common. Here you have
![8 {a}^{3} {b}^{2} = {2}^{3} {a}^{3} {b}^{2}](https://tex.z-dn.net/?f=8%20%7Ba%7D%5E%7B3%7D%20%7Bb%7D%5E%7B2%7D%20%20%3D%20%7B2%7D%5E%7B3%7D%20%7Ba%7D%5E%7B3%7D%20%20%7Bb%7D%5E%7B2%7D%20)
and
![12ab^4 = {2}^{2} \cdot 3a {b}^{4}](https://tex.z-dn.net/?f=12ab%5E4%20%3D%20%20%7B2%7D%5E%7B2%7D%20%20%20%5Ccdot%203a%20%7Bb%7D%5E%7B4%7D%20)
You have 2, a and b in common. Then for each one, you take the smallest power. It gives
Answer:
The correct options are 2 and 4.
Step-by-step explanation:
From the given box plot it is clear that
![\text{Minimum value}=20](https://tex.z-dn.net/?f=%5Ctext%7BMinimum%20value%7D%3D20)
![Q_1=25](https://tex.z-dn.net/?f=Q_1%3D25)
![Median=40](https://tex.z-dn.net/?f=Median%3D40)
![Q_3=50](https://tex.z-dn.net/?f=Q_3%3D50)
![\text{Maximum value}=110](https://tex.z-dn.net/?f=%5Ctext%7BMaximum%20value%7D%3D110)
We know that these number divides the data in four equal parts.
![Q_1=25\%](https://tex.z-dn.net/?f=Q_1%3D25%5C%25)
![Median=50%](https://tex.z-dn.net/?f=Median%3D50%25)
![Q_3=75\%](https://tex.z-dn.net/?f=Q_3%3D75%5C%25)
25% of the data values lies between 50 and 110. Therefore option 1 is incorrect.
Seventy-five percent of the data values lies between 20 and 50. Therefore option 2 is correct.
It is unlikely that there are any outliers. This statement is not true because the is a huge difference between third quartile and maximum value.
Therefore option 3 is incorrect.
The interquartile range is
![IQR=Q_3-Q_1=50-25=25](https://tex.z-dn.net/?f=IQR%3DQ_3-Q_1%3D50-25%3D25)
Therefore option 4 is correct.
The range is
Range = Maximum-Minimum
![Range=110-20=90](https://tex.z-dn.net/?f=Range%3D110-20%3D90)
Therefore option 5 is incorrect.