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Fynjy0 [20]
4 years ago
11

Typically , how do people earn income

Computers and Technology
2 answers:
Mrrafil [7]4 years ago
7 0
People typically earn income by getting a job.
natima [27]4 years ago
3 0
People earn income by getting jobs and working. When they work, they get paid. That's an income
You might be interested in
Construct a class that will model a quadratic expression (ax^2 + bx + c). In addition to a constructor creating a quadratic expr
stich3 [128]

Answer:

Following are the code to this question:

#include <iostream>//header file

#include<math.h>//header file

using namespace std;

class Quadratic//defining a class Quadratic  

{

private:

double a,b,c;//defining a double variable

public:

Quadratic()//defining default constructor

{

a = 0;//assigning value 0  

b = 0;//assigning value 0  

c = 0;//assigning value 0  

}

Quadratic(double a, double b, double c)//defining a parameterized constructor  

{

this->a = a;//use this keyword to hold value in a variable

this->b = b;//use this keyword to hold value in b variable

this->c = c;//use this keyword to hold value in c variable

}

double getA() //defining a get method  

{

return a;//return value a

}

void setA(double a)//defining a set method to hold value in parameter

{

this->a = a;//assigning value in a variable

}

double getB() //defining a get method  

{

return b;//return value b

}

void setB(double b)//defining a set method to hold value in parameter  

{

this->b = b;//assigning value in b variable

}

double getC() //defining a get method

{

return c;//return value c

}

void setC(double c)//defining a set method to hold value in parameter

{

this->c = c;//assigning value in c variable

}

double Evaluate(double x)//defining a method Evaluate to hold value in parameter

{

return ((a*x*x)+(b*x)+c);//return evaluated value

}

double numberOfReal()//defining a method numberOfReal to calculates the real roots

{

return (b*b)-(4*a*c);//return real roots

}

void findroots()//defining a method findroots

{

double d=numberOfReal();//defining double variable to hold numberOfReal method value

if(d<0)//use if block to check value of d less than 0

cout<<"Equation has no real roots"<<endl;//print message

else

{

double r1=(-b+sqrt(numberOfReal()))/(2*a);//holding root value r1

double r2=(-b-sqrt(numberOfReal()))/(2*a);//holding root value r2

if(r1==r2)//defining if block to check r1 equal to r2

cout<<"Equation has one real root that is "<<r1<<endl;//print message with value

else//else block

cout<<"The equation has two real roots that are "<<r1<<" and "<<r2<<endl;////print message with value

}

}

void print()//defining a method print  

{

cout<< a << "x^2 + " << b << "x + " << c <<endl;//print Quadratic equation

}

};

int main()//defining main method  

{

Quadratic q(5,6,1);//creating Quadratic class object that calls parameterized constructor

q.print();//calling print method

cout<<q.numberOfReal()<<endl;//calling method numberOfReal that prints its value

q.findroots();//calling method findroots

cout<<q.Evaluate(-1);//calling method Evaluate that prints its value

return 0;

}

Output:

5x^2 + 6x + 1

16

The equation has two real roots that are -0.2 and -1

0

Explanation:

In the above code, a class "Quadratic" is declared, which is used to define a default and parameter constructor to holds its parameter value.

In the next step, the get and set method is defined that holds and returns the quadratic value, and "Evaluate, numberOfReal, findroots, and print" in the evaluate method a double variable is used as a parameter that returns evaluated value.

In the "numberOfReal" method it calculates the real roots and returns its value. In the "findroots" method a double variable "d" is declared that hold "numberOfReal" value,

and use a conditional statement to check its value, and in the print method, it prints the quadratic equation.

In the main method, the lass object it calls the parameterized constructor and other methods.

5 0
3 years ago
You have been tasked with designing an Ethernet network. Your client needs to implement a very high-speed network backbone betwe
lorasvet [3.4K]

Answer:

A and C

Explanation:

From the above scenario, the Ethernet standards that meet the above guidelines are:

A. 1000BaseSX; and

C. 10GBaseSR.

Cheers

3 0
3 years ago
Draw the flowchart and pseudocode for a program allowing the user to enter a value for one edge of a cube(A box-shaped solid obj
horsena [70]

Answer:

The flowchart, pseudocode and python program all have the same objective.

The flowchart is designed using draw.io (See attachment)

Pseudocode begins here:

1. Start

2. Input Length

3. Area1 = Length * Length

4. Area2 = 6 * Area1

5. Volume = Area1 * Length

6. Print Length

7. Print Area1

8. Print Area2

9. Print Volume

10. Stop

Python Program begins here:

#Prompt user for input

length = float(input("Length of the edge: "))

#Calculate the area of a side

Area1 = length * length

#Calculate the area of the cube

Area2 = 6 * Area1

#Calculate the volume

Volume = Area1 * length

print("Length: "+str(length))

print("Area of a side: "+str(Area1))

print("Area of the cube: "+str(Area2))

print("Volume: "+str(Volume))

Explanation:

The flowchart , pseudocode and python program start by requesting for user input;

This user input is saved in variable length

The surface area of a face is calculated by length * length and saved in Area1; i.e. Area1 = length * length

The surface area of the cube is calculated by 6 * Area1 and saved in Area2. i.e. Area2 = 6 * Area1 = 6 * length * length

The volume of the cube is calculated by Area1 * length and saved in volume. i.e. Volume = Area1 * length = length * length * length

After the surface area of one side of the cube

, the surface area of the whole cube  and the volume of the cube are calculated; the program then prints the user input (length) and each of the calculated parameters.

6 0
3 years ago
A draft is the last version of your story.<br> True<br> False<br><br> Help lol
Bingel [31]

Answer:

false

Explanation:

draft is your practice version

5 0
4 years ago
A movie that contains a combination of audio, video, graphics, and animation is an example of what: 1.hypermedia 2.linear 3.non-
KatRina [158]

Answer:

I think the answer is 1. hyermedia

6 0
3 years ago
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