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3 years ago

Typically , how do people earn income

Computers and Technology

2 answers:

Mrrafil [7]3 years ago

7 0

People typically earn income by getting a job.

natima [27]3 years ago

3 0

People earn income by getting jobs and working. When they work, they get paid. That's an income

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What is Stefen Salvators mom name? For the tvd fans

jekas [21]

Answer:

Lillian "Lily" Salvatore

Explanation:

8 0

2 years ago

Read 2 more answers

Assume that getPlayer2Move works as specified, regardless of what you wrote in part (a) . You must use getPlayer1Move and getPla

kakasveta [241]

Answer:

(1)

public int getPlayer2Move(int round)

{

int result = 0;

//If round is divided by 3

if(round%3 == 0) {

result= 3;

}

//if round is not divided by 3 and is divided by 2

else if(round%3 != 0 && round%2 == 0) {

result = 2;

}

//if round is not divided by 3 or 2

else {

result = 1;

}

return result;

}

(2)

public void playGame()

{

//Initializing player 1 coins

int player1Coins = startingCoins;

//Initializing player 2 coins

int player2Coins = startingCoins;

for ( int round = 1 ; round <= maxRounds ; round++) {

//if the player 1 or player 2 coins are less than 3

if(player1Coins < 3 || player2Coins < 3) {

break;

}

//The number of coins player 1 spends

int player1Spends = getPlayer1Move();

//The number of coins player 2 spends

int player2Spends = getPlayer2Move(round);

//Remaining coins of player 1

player1Coins -= player1Spends;

//Remaining coins of player 2

player2Coins -= player2Spends;

//If player 2 spends the same number of coins as player 2 spends

if ( player1Spends == player2Spends) {

player2Coins += 1;

continue;

}

//positive difference between the number of coins spent by the two players

int difference = Math.abs(player1Spends - player2Spends) ;

//if difference is 1

if( difference == 1) {

player2Coins += 1;

continue;

}

//If difference is 2

if(difference == 2) {

player1Coins += 2;

continue;

}

// At the end of the game

//If player 1 coins is equal to player two coins

if(player1Coins == player2Coins) {

System.out.println("tie game");

}

//If player 1 coins are greater than player 2 coins

else if(player1Coins > player2Coins) {

System.out.println("player 1 wins");

}

//If player 2 coins is grater than player 2 coins

else if(player1Coins < player2Coins) {

System.out.println("player 2 wins");

}

3 0

3 years ago

X = 10<br> y = 20<br> x > y<br> print("if statement")<br> print("else statement")

Eduardwww [97]

I dont really understand what you want to do but im gonna answer it as if I understood it.

If x is 10 and y is 20 then y is larger than x

8 0

3 years ago

Python Coding:

leva [86]

Answer:

# Here we are asking the user for a number two times

userInput1 = input("Enter any #: ")

userInput2 = input("Enter any # again: ")

# We compare if userInput1 is greater than userInput2

if(userInput1 > userInput2):

# Print userInput1 if userInput1 is greather than userInput2

print("First Number: " + userInput1)

# Otherwise, print userInput2

else:

print("Second Number: " + userInput2)

# Initiate a while-loop

while(True):

# The lines below are from above

userInput1 = input("\nEnter any #: ")

userInput2 = input("Enter any # again: ")

if(userInput1 > userInput2):

print("First Number: " + userInput1)

else:

print("Second Number: " + userInput2)

# We ask the user whether they would like to stop

stop = input("\nWould you like to stop? (Yes or No)")

# Compare the String stop with "Yes"

if(stop == "Yes"):

# If true then break

break

Explanation:

The use of \n is unnecesary, but it skips a line and provides more readability.

5 0

2 years ago

Ld' is the instruction with the longest latency on the CPU from Section 4.4 (in RISC-V text). If we modified ld and sd so that t

antiseptic1488 [7]

Answer:

See explaination

Explanation:

The primary factors that influence the program's speed on a new CPU are given as:-

CPU Clock speed where the speed of the process instructions is being measured.

Multi-core which is when the transistors work faster than respective CPU.

Cache which helps to note that the transition of data is smooth and fast.

So, there are two CPUs suppose the old one as 'A' and the modified one as 'B'.

'A' has following features---

It takes more time to execute program as it has more clock cycle time or we can say it has low clocking rate or low speed in terms of MHz or GHz. Clock rate is the inverse of Clock Cycle Time. When you will increase the clocking rate of CPU, it will get faster and then Clock Cycle Time will get reduced.

It has less instructions provided.

'B' has following features----

It takes less time to execute program as it has less clock cycle time or we can say it has high clocking rate or high speed in terms of MHz or GHz.

It has more instructions provided.

The performance of CPU depends upon 2 factors:

The number and types of instructions that are executed by the CPU

How fast the CPU can execute those instructions?

So, overall CPU B is better as it has less execution time than CPU A but the performance will always depend upon the number and type of instructions executed by the CPU so it may vary.

Please refer to attachment for instructions and formulas.

8 0

3 years ago