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Stells [14]
3 years ago
6

Simplify 2^3 x 2^18 A. 2^54 B. 4^54 C. 4^21 D. 2^21

Mathematics
1 answer:
maksim [4K]3 years ago
4 0
When you multiply powers, you add them. You keep the constant (2) the same.

3+18= 21

2^21 <=== the answer

“D” is the answer.

I hope this helps!
~kaikers
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HELP!!!!!!!!!!!!!!!!!!!!!!!!
borishaifa [10]
A is the correct answer
(to find diagonal of a square , you can get help from Pythagorean Theorem)

{10}^{2}  + 10 {}^{2}  =  {x}^{2}  \\ 100 + 100 =  {x}^{2}  \\  {x}^{2}  = 200 \\ x =  \sqrt{200}




good luck
5 0
4 years ago
Can someone help me answer this asap?
Sauron [17]

Answer:

C is an irrational number because it never ends, but does not repeat.

the rest are rational numbers.

Step-by-step explanation:

3 0
3 years ago
In a movie theater, the first row contains 3 seats, the second row contains 6 seats, the third row contains 9 seats, and the fou
yanalaym [24]

Answer:It's an arithmetic sequence with a common difference, d, = 4

A1 = 8

A2 = 8+4 = 12

A3 = 12+4 = 16   = 8+4(3-1) = 8+4(2) = 8+8

AN = A1 + d(N-1)

AN = 8 +4(N-1)  =  the Nth term in the sequence

Step-by-step explanation: hoped it helped

7 0
3 years ago
1. The heights of two right prisms
RoseWind [281]

Answer:

They are not similar

Step-by-step explanation:

To determine whether the prism are similar we need to calculate their volumes

Volume of a prism = Base Area * Height

Volume of the first prism = 18ft *8 * 8ft

Volume of the first prism = 1152ft^2

Volume of the second prism = 30t * 15 * 15ft

Volume of the second prism = 6,750ft^2

Since the volumes are different, the prism are not similar.

3 0
3 years ago
You roll a six-sided die twice. What is the probability of rolling a 2 and then an odd number?
-BARSIC- [3]

Answer:

C) 1/ 12

Step-by-step explanation:

for a fair 6-sided die, for each independent roll, the possible number of outcomes is 1,2,3,4,5,6. I.e there are 6 possible outcomes

Also realize that there is only one "2" out of the 6 possible outcomes.

hence P(roll 2)  = 1/6

Similarly, there are 3 odd numbers (i.e 1, 3, 5) out of the 6 possible outcomes

hence P(roll odd number) = 3 /6 = 1/2

P (roll 2 on first roll then odd number on second roll)

= P(roll 2) x P(roll odd number)

= 1/6 x 1/2

= 1/12

8 0
4 years ago
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