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anzhelika [568]

3 years ago

12

A weather station on the top of a mountain reports that the temperature is currently 0°C and has been falling at a constant rate

of 3°C per hour. What was the temperature 4.5 hours ago ?

1 answer:

schepotkina [342]3 years ago

3 0

Answer:

10.5 degrees Celsius

Step-by-step explanation:

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Tickets to a concert cost $24 before a 5% fee is added.How much are the tickets with the fee?

vagabundo [1.1K]

Answer:

$25.20

Step-by-step explanation:

10%= 2.4 because you divide 24 by 10

So 5%= half 2.4= 1.2

24+1.2=25.20

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A 12 ft ladder is leaning against a building. The ladder makes a 45 degree angle with the building how far up is the building do

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Answer:

The ladder reach a height 8.485 ft.

Step-by-step explanation:

The ladder with the building made right angle triangle

The length of the ladder is the hypotenuse 12 ft.

The angle between the ladder and the building is 45°

The height of the ladder reach is the vertical side of the Δ

∴ h = 12 cos 45° = 6√2 = 8.485 ft.

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The shipping fee is 3.5% of the cost of the items. If the shipping fee is $15.00, the cost of the items is:

MariettaO [177]

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105

Step-by-step explanation:

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3 years ago

What is the midpoint of the segment show below?

USPshnik [31]

Answer:

The answer would be c) (5,1/2)!

Hope this helps!

Brainliest?

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3 years ago

A right pyramid with a regular hexagon base has a height of 3 units If a side of the hexagon is 6 units long, then the apothem i

Setler79 [48]

Answer:

Part a) The slant height is $3\sqrt{2}\ units$

Part b) The lateral area is equal to $54\sqrt{2}\ units^{2}$

Step-by-step explanation:

we know that

The lateral area of a right pyramid with a regular hexagon base is equal to the area of its six triangular faces

so

$LA=6[\frac{1}{2}(b)(l)]$

where

b is the length side of the hexagon

l is the slant height of the pyramid

Part a) Find the slant height l

Applying the Pythagoras Theorem

$l^{2}=h^{2} +a^{2}$

where

h is the height of the pyramid

a is the apothem

we have

$h=3\ units$

$a=3\ units$

substitute

$l^{2}=3^{2} +3^{2}$

$l^{2}=18$

$l=3\sqrt{2}\ units$

Part b) Find the lateral area

$LA=6[\frac{1}{2}(b)(l)]$

we have

$b=6\ units$

$l=3\sqrt{2}\ units$

substitute the values

$LA=6[\frac{1}{2}(6)(3\sqrt{2})]=54\sqrt{2}\ units^{2}$

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3 years ago

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