9514 1404 393
Answer:
1) f⁻¹(x) = 6 ± 2√(x -1)
3) y = (x +4)² -2
5) y = (x -4)³ -4
Step-by-step explanation:
In general, swap x and y, then solve for y. Quadratics, as in the first problem, do not have an inverse function: the inverse relation is double-valued, unless the domain is restricted. Here, we're just going to consider these to be "solve for ..." problems, without too much concern for domain or range.
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1) x = f(y)
x = (1/4)(y -6)² +1
4(x -1) = (y-6)² . . . . . . subtract 1, multiply by 4
±2√(x -1) = y -6 . . . . square root
y = 6 ± 2√(x -1) . . . . inverse relation
f⁻¹(x) = 6 ± 2√(x -1) . . . . in functional form
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3) x = √(y +2) -4
x +4 = √(y +2) . . . . add 4
(x +4)² = y +2 . . . . square both sides
y = (x +4)² -2 . . . . . subtract 2
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5) x = ∛(y +4) +4
x -4 = ∛(y +4) . . . . . subtract 4
(x -4)³ = y +4 . . . . . cube both sides
y = (x -4)³ -4 . . . . . . subtract 4
2x+3=17
subtract 3 from each side
2x+3 -3 = 17 -3
2x = 14
divide by 2 on each side
2x/2 = 14/2
x = 7
Using simple interest, it is found that:
- The total amount paid was of $7,084.8.
- The finance charge was of $584.8.
- The simple interest rate was of 3%.
<h3>Simple Interest</h3>
Simple interest is used when there is a single compounding per time period.
The amount of interest after t years in is modeled by:

In which:
- r is the interest rate, as a decimal.
In this problem, the amount paid was of 36 monthly payments of
$196.80, hence:
36 x 196.80 = $7084.8.
The total amount paid was of $7,084.8.
The original price is of $6,500, hence the finance charge was of:
7084.8 - 6500 = $584.8.
For interest, we have that:
, hence:




The simple interest rate was of 3%.
More can be learned about simple interest at brainly.com/question/25296782
Answer:

Step-by-step explanation:

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