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Mumz [18]
3 years ago
12

How many triangles and how many rectangles form a rectangular pyramid?

Mathematics
2 answers:
blsea [12.9K]3 years ago
8 0
4triangles 1rectangle.
bogdanovich [222]3 years ago
4 0
4 triangles and 1 rectangle
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In the graph above, the coordinates of the vertices of QPR are Q(3, 0), P(5, 6), and R(7, 0). If AQPR is reflected across
ozzi

Answer:

D. (7, 0)

Step-by-step explanation:

The rule for a reflection over the y-axis is (x, y) → (x, -y)

This means that the x-values stay the same while the y-values change.

Q(x, y) → (x, -y)

Q(3, 0) → (3, 0)

Q'(3, 0)

P(x, y) → (x, -y)

P(5, 6) → (5, -6)

P'(5, -6)

R(x, y) → (x, -y)

R(7, 0) → (7, 0)

R'(7, 0)

Therefore, the correct answer is D.

Hope this helps!

7 0
2 years ago
Refer to the previous exercise. The researchers wanted a sufficiently large sample to be able to estimate the probability of pre
Maru [420]

Answer:

<em>The large  sample n = 117.07</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the estimate error (M.E) = 0.08

The proportion (p) = 0.75

q =1-p = 1- 0.75 =0.25

Level of significance = 0.05

Z₀.₀₅ = 1.96≅ 2

<u><em>Step(ii):-</em></u>

The Marginal error is determined by

M.E = \frac{Z_{0.05} \sqrt{p(1-p)}  }{\sqrt{n} }

0.08 = \frac{2 X \sqrt{0.75(1-0.75)}  }{\sqrt{n} }

Cross multiplication , we get

\sqrt{n}  = \frac{2 X \sqrt{0.75(1-0.75)}  }{0.08 }

√n = \frac{2 X0.4330}{0.08} = 10.825

squaring on both sides , we get

n = 117.07

<u><em>Final answer:-</em></u>

<em>The large  sample n = 117.07</em>

6 0
2 years ago
What are the next three terms in the sequence 2, -4, 8, -16, 32, ...? A. -128, 256, -512 B. 160, 320, 640 C. 160, -320, 640 D. -
miv72 [106K]
Common ratio is -2

next 3 terms :
32 * -2 = -64
-64 * -2 = 128
128 * -2 = -256

answer is D
7 0
3 years ago
Read 2 more answers
The Eco Pulse survey from the marketing communications firm Shelton Group asked individuals to indicate things they do that make
Bad White [126]

Answer:

a) There is a probability of 42% that the person will feel guilty for only one of those things.

b)There is a probability of 46% that a randomly selected person will not feel guilty for either of these reasons

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, for those people that will feel guilty about wasting food.

-Set B, for those people that will feel guilty about leaving lights on when not in a room.

The most important information is that there is a .12 probability that a randomly selected person will feel guilty for both of these reasons. It means that P(A \cap B) = .12.

The problem also states that there is a .39 probability that a randomly selected person will feel guilty about wasting food. It means that P(A) = 0.39. The probability of a person feeling guilty for only wasting food is PO(A) = .39-.12 = .27.

Also, there is a .27 probability that a randomly selected person will feel guilty about leaving lights on when not in a room. So, the probability of a person feeling guilty for only leaving the lights on is PO(B) = 0.27-0.12 = 0.15.

a) What is the probability that a randomly selected person will feel guilty for either wasting food or leaving lights on when not in a room?

This is the probability that the person feels guilt for only one of those things, so:

P = PO(A) + PO(B) = 0.27 + 0.15 = 0.42 = 42%

b) What is the probability that a randomly selected person will not feel guilty for either of these reasons

The sum of all the probabilities is always 1. In this problem, we have the following probabilies

- The person will not feel guilty for either of these reasons: P

- The person will feel guilty for only one of those things:  PO(A) + PO(B) = 0.42

- The person will feel guilty for both reasons: PB = 0.12

So

`P + 0.42 + 0.12 = 1

P = 1-0.54

P = 0.46

There is a probability of 46% that a randomly selected person will not feel guilty for either of these reasons

4 0
3 years ago
PLEASE HELP FAST! THX
mr Goodwill [35]

Answer:

3 ,5 , and 2

Step-by-step explanation:

Hope it helps :)

7 0
3 years ago
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